Ask questions and get helpful answers.

The velocity graph of a particle moving along the x-axis is shown. The particle has zero velocity at t=0.00s and reaches a maximum velocity, vmax, after a total elapsed time, t total. If the initial position of the particle is x0 =9.35m, the maximum velocity of the particle is vmax=29.3m/s, and the total elapsed time is t total=29.9s, what is the particle's position at t=19.9s?

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
4 answers
  1. the graph is not shown.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. the graph is a straight line

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. If the velocity versus time is straight, then its slope, the acceleration, is constant

    a = change in v/change in t
    = (29.3 - 0)/29.9
    calculate a

    v = Vi + a t
    but Vi = 0
    so at t = 19.9
    v = 0 + a (19.9)

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. the graph is not shown.

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.