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Create an immaculate mathematics themed visual representation. Start with an empty classroom blackboard. Sketch an Arithmetic Progression (A.P.) in the center. The A.P should have exactly 11 terms. To represent the sum, add a simple equation to depict '11 terms sum = 891' with each term followed by the '+' symbol. Show a discontinuity to illustrate skipped terms, then draw the 28th and 45th terms, with an arrow pointing towards them for emphasis. Fill the line with points spaced equivalently to symbolize the common difference of 15. Do not include any text beyond what's necessary to illustrate the problem.

the sum of 11 terms of an A.P is 891. find the 28th and 45th terms if the common difference is 15

Use you sum(n) terms formula

(11/2)(2a + 10d) = 891
but d = 15
(11/2)(2a + 150) = 891
11(2a + 150) = 1782
2a + 150 = 162

continue

once you have a, just use your formula
term(28) = a + 27d = ....
etc

The sum of 11 term of an A. P is 891.Find the 28th and 45th term.If the common difference is 15

The sum of 11 term of an A.P is 891.find the 28 and 45 if the common different is 15

show teh working

I don't understand please

solving with Sum (n)term formulea.(11/2)(2a+10d)=891. but remember d=15 (11/2)(2a+150)=5.5(2a+150)=891. 11(2a+150)=1782 and 2a+150=162

How is the 28th term lower than the 11th term

show me the solving

the sum of 11 terms of an a.p is 891 find the 28 and 45 terms if the common difference ir 15

I don't understand please