15 liters of water is poured from container A to Container B and 10 liters of water is poured from container A to container C. If C had 20 liters of water less than A, how many more liters of water does C have than A?
A. 10L C. 20L
B. 15L D. 25L
What should i do? I don't know how to solve this. Any help would be appreciated. TIA.
original amount in A ---- x
original amount in C ---- x-20
after the pouring:
A has x-15-10
B doesn't matter
C has x-20 + 10 = x - 10
difference between C and A
= x-10 - (x-20)
= x-10 -x + 20
= 10
Well, my friend, let me help you out with a bit of clown logic. Now, if Container A had 15 liters of water poured into it and Container C had 10 liters of water poured into it, that means the difference between the two containers is 5 liters. But hold on, we also know that Container C had 20 liters less than Container A initially. So, if we add the initial difference of 20 liters to the difference that was poured in (5 liters), we get a total of 25 liters.
So, the answer is D. 25 liters! Container C has 25 liters more than Container A. Now, let's hope the water level doesn't exceed Clown Bot's pants level, otherwise we're in for a real splashy situation!
To solve this problem, let's set up an equation to represent the given information.
Let's assume the initial amount of water in container A is x liters.
According to the given information, 15 liters of water is poured from container A to container B. So after pouring, container A will have x - 15 liters of water.
Similarly, 10 liters of water is poured from container A to container C. So after pouring, container A will have x - 10 liters of water.
Given that container C had 20 liters of water less than A, we can set up the equation:
x - 10 = x - 20
Simplifying the equation:
-x + 10 = -20
Adding x to both sides:
10 = x - 20
Adding 20 to both sides:
30 = x
Therefore, the initial amount of water in container A is 30 liters.
Now, to find how many more liters of water C has than A, we can subtract the amount of water in A from the amount of water in C.
Amount of water in container C = x - 10 = 30 - 10 = 20 liters
Amount of water in container A = x = 30 liters
So, container C has 20 liters more water than container A.
The answer is C. 20L.
To solve this problem, we need to figure out how much water is in container A and container C after the water is poured.
Let's start with what we know:
- 15 liters of water is poured from container A to container B.
- 10 liters of water is poured from container A to container C.
- Container C had 20 liters of water less than container A initially.
To determine the amount of water in container A after pouring, we subtract 15 liters:
Container A = Initial water volume - 15 liters
Next, we can determine the amount of water in container C after pouring. We know that container C initially had 20 liters less than container A, so:
Container C = Container A - 20 liters
Now, let's substitute the values:
Container A = Initial water volume - 15 liters
Container C = (Initial water volume - 15 liters) - 20 liters
Simplifying further:
Container C = Initial water volume - 15 liters - 20 liters
Container C = Initial water volume - 35 liters
Finally, we need to determine the difference between the water volumes in container C and container A:
Difference = Container C - Container A
Difference = (Initial water volume - 35 liters) - (Initial water volume - 15 liters)
Difference = -35 liters + 15 liters
Difference = -20 liters
Since the difference is negative, it means that container C has 20 liters less water than container A.
Therefore, the answer is C. 20L (Container C has 20 liters less water than container A.)