1. Solve the equation below for x interms of a

4(ax+3)-3ax=25+3a

2. The formula for the sum of the degree measures of the interior angles of a polygon is S=180(n-2). Solve for n, the number of sides of the polygon, in terms of S.

IM STRUGGLING PLEASE HELP

1.

4 ( ax + 3 )-3 ax = 25 + 3a

4 * ax + 4 * 3 - 3 ax = 25 + 3a

4 ax + 12 - 3 ax = 25 + 3a

4 ax - 3 ax + 12 = 25 + 3a

ax + 12 = 25 + 3a Subtract 12 to both sides

ax + 12 - 12 = 25 + 3a - 12

ax = 25 - 12 + 3a

ax = 13 + 3a Subtract 3a to both sides

ax - 3a = 13 + 3a - 3a

ax - 3a = 13

a ( x - 3 ) = 13 Divide both sides by a

x - 3 = 13 / a Add 3 to both sides

x - 3 + 3 = 13 / a + 3

x = 13 / a + 3 = 13 / a + 3a / a

x = ( 13 + 3a ) / a

2.

S = 180 ( n - 2 ) Divide both sides by 180

S / 180 = n - 2 Add 2 to both sides

S / 180 + 2 = n - 2 + 2

S / 180 + 2 = n

n = S / 180 + 2

bosianian it said solve in terms of S

I solved it like:

S=180(n-2) Distribute 180
S=180n-360 Add 360
S+360=180n Divide by 180
S+2=n
Iā€™m confused as to what I am doing wrong.

1. Sure, let's solve the equation using some mathematical clownery!

We have 4(ax + 3) - 3ax = 25 + 3a

Let's start by distributing 4 to the terms inside the parentheses:

4ax + 12 - 3ax = 25 + 3a

Combining like terms, we get:

ax + 12 = 25 + 3a

Now, let's isolate the terms with "x" on one side of the equation:

ax - 3a = 25 - 12

ax - 3a = 13

Finally, let's factor out the "x" on the left side of the equation:

x(a - 3) = 13

Now, to solve for x, we can divide both sides of the equation by (a - 3):

x = 13 / (a - 3)

And there you have it! The solution for x in terms of a is x = 13 / (a - 3).

2. Now let's move on to the second question!

The formula for the sum of the degree measures of the interior angles of a polygon is S = 180(n - 2). We need to solve for n in terms of S.

To do this, let's start by isolating the variable n.

S = 180(n - 2)

Distribute 180 to the terms inside the parentheses:

S = 180n - 360

Now, let's get rid of the -360 term by moving it to the other side:

S + 360 = 180n

To simplify further, let's divide both sides by 180:

(S + 360) / 180 = n

Simplifying that, we get:

n = (S + 360) / 180

And there you have it! The solution for n in terms of S is n = (S + 360) / 180.

Remember, even if math is confusing sometimes, laughter is always the best solution! Keep smiling!

Of course! I'll help you solve both equations step by step.

1. Solve the equation 4(ax+3)-3ax=25+3a for x in terms of a:

First, let's simplify the equation by expanding and combining like terms:

4(ax+3)-3ax=25+3a
4ax + 12 - 3ax = 25 + 3a
ax + 12 = 25 + 3a

Next, let's isolate the terms with x on one side of the equation:

ax - 3a = 25 - 12
ax - 3a = 13

Now, we can factor out the common variable, a, from the left side:

a(x - 3) = 13

Finally, we can solve for x by dividing both sides of the equation by a:

(x - 3) = 13/a

So, x in terms of a is:

x = 13/a + 3

2. Solve the equation S = 180(n-2) for n in terms of S:

To solve for n, we need to isolate it on one side of the equation. Let's go step by step:

S = 180(n-2)

First, distribute the 180 to both terms inside the parentheses:

S = 180n - 360

Next, let's isolate n by moving the constant term -360 to the other side of the equation:

S + 360 = 180n

To solve for n, we need to get rid of the coefficient 180. Divide both sides of the equation by 180:

(S + 360)/180 = (180n)/180

Simplifying further:

(S + 360)/180 = n

Now, we can simplify the equation:

n = (S + 360)/180

So, n in terms of S is:

n = (S + 360)/180

I hope this helps! Let me know if you have any further questions.

Where you got the s from ?

these just use the normal sequences of operations...

4(ax+3)-3ax=25+3a
4ax+12-3ax = 25+3a
ax+12 = 25+3a
ax-3a = 25-12
a(x-3) = 12
a = 13/(x-3)

S=180(n-2)
S = 180n-360
S+360 = 180n
n = (S+360)/180 = S/180 + 2