The volume of a gas in cubic centimeters, V, varies inversely with the pressure of the gas in liters per square centimeter, p.

When the volume of the gas is 16 cm3, its pressure is 20 L/cm2. Find the volume of the gas when the pressure is 2.2 L/cm2.

What is an L ?? Perhaps a Newton??? if cm^2/then D for Dyne

anyway

v = k/p

16 cm^3 = k / 20L/cm^2
k = 16*20

v = 16*20/2.2 = 145 cm^3

To solve this problem, we can use the inverse variation formula, which states that if two variables, V and p, vary inversely, then their product is constant. Mathematically, this can be represented as V * p = k, where k is the constant of variation.

In order to find the volume of the gas when the pressure is 2.2 L/cm2, let's first find the value of k using the initial values provided in the problem.

When the volume of the gas is 16 cm3, its pressure is 20 L/cm2. Plug these values into the inverse variation formula:
16 * 20 = k
320 = k

Now that we have found the value of k, we can use the formula to find the volume of the gas when the pressure is 2.2 L/cm2.

Let V2 be the volume of the gas when the pressure is 2.2 L/cm2. We are given that the pressure is 2.2 L/cm2. Again, we plug in these values into the inverse variation formula and solve for V2:

V2 * 2.2 = 320
V2 = 320 / 2.2
V2 ≈ 145.45 cm3

Therefore, when the pressure is 2.2 L/cm2, the volume of the gas is approximately 145.45 cm3.

V = k/P, so

VP = k, a constant

so, you want V so that

2.2V = 20*16

By the way, L/cm^2 is not pressure. 1L = 1000cm^3, so L/cm^2 = cm

Pressure is force/area, as in N/m^2

I've never heard of this L/cm^2 unit. But then, I'm not a physicist...

so the answer would be v=145.45