the sides of a triangle are consecutive integers.If its perimeter is 126cm.find the lengths of the sides.

x + x+1 + x+2 = 126

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126cm = x + x + 1 + x + 2

126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x

The 3 consecutive sides of a triangle is 41,42 and 43.

126cm = x + x + 1 + x + 2

126 = 3x + 3
126 – 3 = 3x
123 = 3x
123/3 = 3x/3
41 = x

The 3 consecutive sides of a triangle are 41,42 and 43.

To solve this problem, we can use the information given and set up an equation to find the lengths of the sides.

Let's assume that the three consecutive integers are n, n+1, and n+2.

The perimeter of a triangle is the sum of the lengths of its three sides. Therefore, we can set up the following equation:

n + (n + 1) + (n + 2) = 126

Simplifying the equation, we get:

3n + 3 = 126

Subtracting 3 from both sides, we have:

3n = 123

Now, let's solve for n by dividing both sides by 3:

n = 123 / 3

n = 41

So, the first side of the triangle is 41 cm, the second side is 42 cm (41 + 1), and the third side is 43 cm (41 + 2 cm).