Cylinder A has radius r and height h. Cylinder B has radius 2r and height 2h. How many times greater is the surface area of Cylinder B than the surface area of Cylinder A?

I have no idea how to start doing this problem. Are there any tips on how to start?

Ya mom

4 times greater hope this helps

surface are cylinded = 2*PI*(2r)+2PI*r*h

that is if the cylinder ends are counted.
Surface area of lateral surface only: PI*2r*h

so if it is a cylinder with ends open, now begs the question does the interior surface area matter? If so, double the above.

if exterior lateral side area only, then Area= PI*2(2r)*2H

looks like Area quadrupled.

2*2=4

(educated guess)= 4

To find out how many times greater the surface area of Cylinder B is compared to Cylinder A, we need to calculate the surface area for both cylinders first. Let's start with Cylinder A.

The formula for the surface area of a cylinder is given by:
Surface Area = 2πr^2 + 2πrh

For Cylinder A:
Surface Area A = 2πr^2 + 2πrh

Now we can calculate the surface area for Cylinder B using the same formula:

For Cylinder B:
Surface Area B = 2π(2r)^2 + 2π(2r)(2h)

Simplifying the equation, we get:
Surface Area B = 8πr^2 + 8πrh

Now we have both surface areas, Surface Area A and Surface Area B. To find how many times greater the surface area of Cylinder B is compared to Cylinder A, we can divide the Surface Area B by Surface Area A:

Surface Area B / Surface Area A = (8πr^2 + 8πrh) / (2πr^2 + 2πrh)

Now we can simplify further and cancel out terms if possible.

Surface Area B / Surface Area A = (4r^2 + 4rh) / (r^2 + rh)

So, the surface area of Cylinder B is (4r^2 + 4rh) / (r^2 + rh) times greater than the surface area of Cylinder A.

Now, if you have specific values for r and h, you can substitute them into the formula and calculate the ratio.