The probability that a person stopping at petrol pump will get his tyres checked is 0.12, the probability that he will get his oil checked is 0.29 and the probability that he will get both checked is 0.07.
A) what is the probability that a person stopping at this pump will have neither his tyres nor oil checked?
B) find the probability that a person get his oil as well as tyres checked.
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
A) (1-.12)(1-.29) = ?
B) It is in your data, .07.
mesfine
A) Well, if the probability of getting the tyres checked is 0.12 and the probability of getting the oil checked is 0.29, then the probability of getting neither checked would be the opposite of both happening, which is 1 - (0.12 + 0.29 - 0.07). So, the probability of having neither his tyres nor oil checked would be the remaining probability beyond that. Let's crunch the numbers... *tap tap tap* ...Ah, my red nose! The probability is 0.68!
B) Ah, the probability of getting both the tyres and oil checked! Well, that's already given as 0.07. So, if you want the probability of both events happening, then you've got it right there, my friend. A clown never jokes about math!
To find the probability in both scenarios, we need to understand the concepts of union and intersection of events and apply them to the given information.
A) The probability that a person will have neither his tyres nor oil checked can be found by subtracting the probability of having either or both checked from 1.
Let's denote:
P(T) = Probability of getting tyres checked = 0.12
P(O) = Probability of getting oil checked = 0.29
P(T ∩ O) = Probability of getting both tyres and oil checked = 0.07
To find the probability of neither tyres nor oil being checked, we can use the formula:
P(¬T ∩ ¬O) = 1 - P(T ∪ O)
The union of two events, denoted as ∪, represents the probability of at least one of the events happening. Therefore,
P(T ∪ O) = P(T) + P(O) - P(T ∩ O)
Substituting the given values, we have:
P(T ∪ O) = 0.12 + 0.29 - 0.07 = 0.34
Finally, we can find P(¬T ∩ ¬O):
P(¬T ∩ ¬O) = 1 - P(T ∪ O) = 1 - 0.34 = 0.66
Therefore, the probability that a person stopping at this pump will have neither his tyres nor oil checked is 0.66.
B) The probability that a person will get both his oil and tyres checked can be found by taking the intersection of the two events.
Let's denote:
P(T ∩ O) = Probability of getting both tyres and oil checked = 0.07
Therefore, the probability that a person will get his oil as well as tyres checked is 0.07.
(A)0.34
(B)0.24
Answer:
Probablity that the person will get both things checked = 0.035
Step-by-step explanation:
The statement given in the end is not correct considering the first two statements as valid.
Statement 1
Probability that a person stopping at a petrol pump will get his tyres checked is 0.12
Statement 2
Probability that a person stopping at a petrol pump will get his tyres checked is 0.29
Statement 3
Probability that a person stopping at a petrol pump will get his tyres and oil checked is 0.07 (incorrect)
Probability that the person will get both things checked = 0.12 x 0.29 = 0.035