A is a solution of tetraoxosulphate(iv)acid.B contains 3.95g of sodium trioxocarbonate(iv) in 750cm3 of solution.if 22.70cm3 of the tetraoxosulphate(iv)acid neutralized 25.0cm3 of sodiumtrioxocarbonate(iv).calculate the concentration of

i) B in moldm-3
ii) A in moldm-3

What you REALLY mean is H2SO4 (sulfuric acid) and Na2CO3 (sodium carbonate).

H2SO4 + Na2CO3 ==> H2O + CO2 + Na2SO4

mols Na2CO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols Na2SO4 to mols H2SO4. You can see that is a 1:1 ratio.
Then M H2SO4 = mols H2SO4/L H2SO4. That's A.
M of B is mols B/L B.
Note: moldm^-3 = mols/L = Molarity = M.

To calculate the concentration of solution B in moldm-3 and the concentration of solution A in moldm-3, we need to use the information provided in the question. Let's start with calculating the concentration of solution B first.

i) Concentration of B in moldm-3:

Step 1: Convert the mass of sodium trioxocarbonate (IV) to moles.
Given: Mass of sodium trioxocarbonate (IV) = 3.95g
The molar mass of sodium trioxocarbonate (IV) (Na2CO3) is:
Na = 22.99 g/mol
C = 12.01 g/mol
O = 16.00 g/mol

Molar mass of Na2CO3 = (2 * Na) + C + (3 * O) = (2 * 22.99) + 12.01 + (3 * 16.00) = 105.99 g/mol

Moles of sodium trioxocarbonate (IV) = Mass / Molar mass
Moles of sodium trioxocarbonate (IV) = 3.95g / 105.99 g/mol

Step 2: Calculate the concentration of B in moldm-3 using the volume of the solution.
Given: Volume of B solution = 750 cm3 = 0.75 dm3

Concentration (mol/dm3) = Moles / Volume
Concentration (mol/dm3) = Moles of sodium trioxocarbonate (IV) / Volume of B solution
Concentration (mol/dm3) = (3.95g / 105.99 g/mol) / 0.75 dm3

ii) Concentration of A in moldm-3:

Step 1: Calculate the number of moles of sodium trioxocarbonate (IV) reacted with tetraoxosulphate (IV) acid.
Given: Volume of tetraoxosulphate (IV) = 22.70 cm3
Volume of sodium trioxocarbonate (IV) = 25.0 cm3

The reaction equation is:
H2SO4 + Na2CO3 -> Na2SO4 + H2O + CO2

From the equation, we can see that the mole ratio between tetraoxosulphate (IV) acid and sodium trioxocarbonate (IV) is 1:1.

Moles of sodium trioxocarbonate (IV) = Moles of tetraoxosulphate (IV) acid
Moles of sodium trioxocarbonate (IV) = Concentration of tetraoxosulphate (IV) acid * Volume of tetraoxosulphate (IV) acid

Step 2: Calculate the concentration of A in moldm-3 using the volume of the solution.
Given: Volume of A solution = unknown

We can use the information to calculate the concentration of A by performing a mole-to-mole comparison.

Concentration (mol/dm3) = Moles / Volume
Concentration (mol/dm3) = Moles of sodium trioxocarbonate (IV) / Volume of A solution

Since the volume of solution A is not given in the question, we cannot determine the concentration of solution A in mole/dm3 with the information provided.

Please provide the volume of solution A in order to calculate its concentration.

To find the concentration of B (sodium trioxocarbonate(IV)) in moldm-3 and the concentration of A (tetraoxosulphate (IV) acid) in moldm-3, we'll need to use the concept of stoichiometry and the volume of the solutions used.

First, let's calculate the number of moles of sodium trioxocarbonate(IV) (B).

Step 1: Find the molar mass of sodium trioxocarbonate(IV) (Na2CO3). The atomic masses are: Na = 23, C = 12, and O = 16.

Molar mass of Na2CO3 = (2 × 23) + 12 + (3 × 16) = 106 g/mol

Step 2: Calculate the number of moles of sodium trioxocarbonate(IV) (B).

Number of moles (B) = mass of B / molar mass of B
Number of moles (B) = 3.95 g / 106 g/mol

i) To find the concentration of B (sodium trioxocarbonate(IV)) in moldm-3:

Step 3: Convert the volume of the solution B from cm3 to dm3.

Volume (B) = 750 cm3 = 750 / 1000 dm3 = 0.75 dm3

Step 4: Calculate the concentration of B in moldm-3.

Concentration (B) = Number of moles (B) / Volume (B)
Concentration (B) = (3.95 g / 106 g/mol) / 0.75 dm3

ii) To find the concentration of A (tetraoxosulphate (IV) acid) in moldm-3:

Step 5: Convert the volume of tetraoxosulphate(IV) acid (A) from cm3 to dm3.

Volume (A) = 22.70 cm3 = 22.70 / 1000 dm3 = 0.0227 dm3

Step 6: Calculate the concentration of A in moldm-3.

Concentration (A) = Volume (B) / Volume (A) × Concentration (B)
Concentration (A) = 0.0227 dm3 / 0.0250 dm3 × Concentration (B)

Remember to substitute the value of Concentration (B) calculated in step 4 into this equation to find Concentration (A) in moldm-3.

By following these steps and performing the calculations, you will be able to determine the concentration of solution B (sodium trioxocarbonate(IV)) in moldm-3 (i) and the concentration of solution A (tetraoxosulphate (IV) acid) in moldm-3 (ii).