The heat of fusion for water is 3.3 x 105 J/kg. How much heat energy is needed to can 3kg of ice at 0°C to water at 0°C? Show your work.

Help please!! Don't give the answer, but please help me find the answer?! Thanks

UPDATE: is this correct?

c = Q/mΔT
330000 = Q/3*0
Q = 330000*3*0
Q = 0

there is no temp change involved here, just the heat to melt at 0

Q = mass * heat of fusion
= 3 * 3.3*10^5
= 9.9 * 10^5 Joules

Sure, I can help you with that! To find the amount of heat energy needed to convert 3kg of ice at 0°C to water at 0°C, we need to calculate the heat of fusion required.

The formula to calculate the heat energy (Q) is given by:
Q = m * ΔHf

Where:
Q = heat energy
m = mass of the substance
ΔHf = heat of fusion

Plugging in the given values:
m = 3kg
ΔHf = 3.3 x 10^5 J/kg

Q = 3kg * (3.3 x 10^5 J/kg)

Now, multiply the mass (3kg) by the heat of fusion (3.3 x 10^5 J/kg) to find the heat energy required.

Of course! I'd be happy to help you find the answer.

To calculate the amount of heat energy needed to change a substance from one phase to another, we can use the formula:

Q = m * H

where:
Q represents the heat energy in joules (J),
m represents the mass of the substance in kilograms (kg),
and H represents the specific heat of fusion or vaporization for the substance in joules per kilogram (J/kg).

In your case, the heat of fusion for water is given as 3.3 x 10^5 J/kg, and the mass of ice to be melted is 3 kg.

So, let's substitute these values into the formula:

Q = 3 kg * (3.3 x 10^5 J/kg)

To calculate this, you will need to multiply the mass (3 kg) by the heat of fusion (3.3 x 10^5 J/kg). This will give you the amount of heat energy required to convert the ice into water.

By performing this calculation, you will find the answer to your question.