Find the equation of a Parabola with Vertex: (-2,4) and directrix: y=7
7-4 = 3 and directrix is above vertex (sheds water) so a = -3
(x+2)^2 =-4*3 (y-4)^2 = -12(y-4)^2
Answer this Question
How do I find vertex, focus and directrix for the following functions? y^2−16y=12x−8^2 x^2+16x=4y−24 (x−2)^2=12(y−2)
- asked by Jamie
- 904 views
.Find the standard equation of the hyperbola whose conjugate axis is on the directrix of the parabola 𝑦^2 + 12𝑥 + 6𝑦 = 39, having the focus of the parabola as one of its foci, and the vertex of the parabola as one of its vertices.
- asked by uwu
- 377 views
Can someone please help me with these? 1. What are the focus and directrix of the parabola with the equation y=1/12 xsquared 2. what is an equation of a parabola with a vertex at the origin and directrix y=19/4 3. What are the focus and directrix of the
- asked by Anonymous
- 3,041 views
Suppose a parabola has a vertex (-4,7) and also passes through the point (-3,8) Write the equation of the parabola in vertex form. f(x)=a(x-h)^2+k I believe h=-4 k=7 Not sure what to do from here.
- asked by Lee
- 2,862 views
Algebra 1- 8th Grade
What is the relationship between the x-intercepts of a parabola and its vertex's x-coordinate?
- asked by Nancy
- 1,418 views
Find the equation of the parabola whose axis is horizontal, vertex on the y-axis and which passes through (2,4) and (8,-2).
- asked by AJ
- 1,414 views
a quadratic equation can be written in vertex form or in standard form. sometimes one form is more beneficial than the other. identify which form would be more helpful if you needed to do each task listed below and explain why. a. factor the equation. b.
- asked by wefewfwefewf
- 8,958 views
What is the vertex of a parabola? How do you determine the vertex of the parabola?
- asked by GGIFT
- 5,948 views
2 towers of a suspension bridge are 1000 meters apart and are 160 meters high. The cable between 2 towers hangs in a shape of parabola, which at its lowest is 40meters above the road. A. Find the equation of the parabola, if we put a coordinate system so
- asked by Casper
- 2,917 views
Find an equation of the parabola with vertex at the origin. Passes through the point (4,6); horizontal axis. I know it has to be y^2=4px. But I don't know what to do with (4,6). Please show step by step. Thanks.
- asked by Vincent
- 1,519 views
Find the vertex and focus of the parabola. (x^2)-(24y) = 0
- asked by barb
- 1,584 views
Find the equation of the parabola with it's focus at (-4,7) and directrix y=1 Is y+4=-1/12(x-4)^2 Right or is it y-7=1/24(x=a)^2 y-4=1/12(x+4)^2 y-3=1/24(x+4)^2
- asked by Brittany
- 637 views
Find the focus, directrix, and focal diameter of the parabola. x2 = 5y focus (x, y) = 0, 5/4 directrix:y=-5/4 focal diameter=5 Sketch its graph? my answers seem to be correct but i cannnot sketch the graph correctly.
- asked by Ama
- 2,610 views
Find the equation of a parabola with vertex (3,1) and focus (5,1)
- asked by Anonymous
- 776 views
Find the equation of the parabola, in standard form, whose Vertex (2, 1), ends of the latus rectum (-1, -5) and (-1, 7).
- asked by amikhailov
- 649 views
A quadratic equation can be written in vertex form or in standard form. Sometimes one form is more beneficial than the other. Identify which form would be more helpful if you needed to do each task listed below and explain why. a- factor the equation b-
- asked by Steve
- 1,888 views
Find the focus, directrix, and focal diameter of the parabola. y2 = 8x
- asked by Ama
- 1,956 views
what is an equation of a parabola with the given vertex and focus? Vertex: (-2,5); focus: (-2,6)
- asked by jennifer
- 9,575 views
x^2+6x+8y=7 Find the: Direction: Vertex: Focus: Axis of Symmetry: Directrix:
- asked by Leona
- 5,110 views
Using the given information write the equation of parabolas: The parabola has focus (0, 6) and vertex at the origin;
- asked by hey
- 1,716 views