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Tickets for a certain show cost

​$15​, $24​,
​or, for VIP​ seats,
​$41.
If
ninenine
times as many
​$15
tickets were sold as VIP​ tickets, and the number of
​$15
tickets sold was
55
more than the sum of the number of
​$24
tickets and VIP​ tickets, sales of all three kinds of tickets would total
​$46 comma 46,152.
How many of each kind of ticket would have been​ sold?

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1 answer

  1. If the number of seats for the categories is x,y,z then just list the data:

    x = 9z
    x = 55+y+z
    15x+24y+41z = 46152

    Now just solve for x,y,z

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