Tickets for a certain show cost
$15, $24,
or, for VIP seats,
$41.
If
ninenine
times as many
$15
tickets were sold as VIP tickets, and the number of
$15
tickets sold was
55
more than the sum of the number of
$24
tickets and VIP tickets, sales of all three kinds of tickets would total
$46 comma 46,152.
How many of each kind of ticket would have been sold?
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1 answer

If the number of seats for the categories is x,y,z then just list the data:
x = 9z
x = 55+y+z
15x+24y+41z = 46152
Now just solve for x,y,z 👍
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answered by Steve
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