Hi, I have this question to answer and I am just really confused I don't know where to begin we haven't had a question like this so I'm totally bewildered. Anyway here is my question. Any help is greatly appreciated! Thank you so much for your time!!!

Ellen is at a hydroplane boat show starting from 1.0 miles away the boat drives toward her and then passes her the boat travels at a constant rate of 70 miles per hour the distance of the boat from ellen is given by d=|1.0-70t| at what time is the boat 0.15 miles from ellen calculate your answers in seconds.

Answer choices:

A: 42 seconds and 61 seconds
B: 40 seconds and 50 seconds
C: 437 seconds and 591 seconds
D: 43.7 seconds and 59.1 seconds

The boat will be .15 miles from Ellen coming and going away.

So
1 - 70t = .15 OR -1 + 70t = .15
t = .01214... hrs or t = .01642.. hrs
t = .01214(3600) sec or t = .01642(3600) sec
t = 43.7 sec OR t = 59.1 sec

Reiny my man all ur answers r wrong

This is correct it is D.

Thanks Reiny!!

The answers are

1. A
2. D
3. E
4. G

Ah, the joys of a hydroplane boat show! Let's dive into this question, shall we?

So, we have the distance of the boat from Ellen given by the equation d = |1.0 - 70t|. In this equation, d represents the distance and t represents the time in hours.

Now, the question asks us when the boat is 0.15 miles from Ellen. In other words, when is d equal to 0.15? We can set up the equation like this:

0.15 = |1.0 - 70t|

To solve this equation, we can split it into two cases:

Case 1: 1.0 - 70t = 0.15
Case 2: 1.0 - 70t = -0.15

Let's start with Case 1:
1.0 - 70t = 0.15
Subtract 1.0 from both sides:
-70t = -0.85

Divide both sides by -70 to solve for t:
t = 0.85 / 70

Now, let's move on to Case 2:
1.0 - 70t = -0.15
Subtract 1.0 from both sides:
-70t = -1.15

Divide both sides by -70 to solve for t:
t = 1.15 / 70

So, in seconds, the boat is 0.15 miles from Ellen at approximately t = 0.85 / 70 seconds and t = 1.15 / 70 seconds.

Now, let's take a look at the answer choices:

A: 42 seconds and 61 seconds - Nope, these don't match our calculations.
B: 40 seconds and 50 seconds - Nope, these don't match our calculations either.
C: 437 seconds and 591 seconds - Well, these aren't even close to our calculations.
D: 43.7 seconds and 59.1 seconds - Ah, here we go! These match our calculations pretty well.

So, the correct answer is option D: 43.7 seconds and 59.1 seconds. Now, grab a life jacket and enjoy the hydroplane boat show!

To solve this question, we need to find the time at which the boat is 0.15 miles away from Ellen.

First, let's set up the equation using the distance formula, which is given as d = |1.0 - 70t|. The absolute value is used because the boat can be either in front of or behind Ellen.

The distance between the boat and Ellen is given as 0.15 miles. So we can write the equation as:
0.15 = |1.0 - 70t|

To solve for t, let's eliminate the absolute value by considering both positive and negative cases.

Case 1: When 1.0 - 70t is positive, the equation becomes: 1.0 - 70t = 0.15
Simplify and solve for t:
-70t = -0.85
t = (-0.85) / (-70)
t ≈ 0.01214 hours

To convert hours to seconds, multiply by 60 (minutes) and 60 (seconds):
t ≈ 0.01214 * 60 * 60 ≈ 43.7 seconds

Case 2: When 1.0 - 70t is negative, the equation becomes: -(1.0 - 70t) = 0.15
Simplify and solve for t:
1.0 - 70t = -0.15
-70t = -1.15
t = (-1.15) / (-70)
t ≈ 0.01643 hours

Again, convert hours to seconds:
t ≈ 0.01643 * 60 * 60 ≈ 59.1 seconds

Therefore, the boat is 0.15 miles away from Ellen at approximately 43.7 seconds and 59.1 seconds. So the correct answer choice is D: 43.7 seconds and 59.1 seconds.

Your Welcome everybody

heres the rest
C
2. A
3. D
4. B or C
5. D
6. C
7. D
8. B
9. C
10. D?
11. A
12. A
13.A
14. D