I need someone to show me how to work these two problems out.
30. find the hypotenuse of a right triangle whose sides measure 9 and 12: i came up with the answer 15 but i honestly forgot how i got this answer please let me know what i did wrong and work the problem for me.
33. find the median of the set of numbers: 2,3,5,6,10 the answer i got for this was the 5 is the median number because i did not have to rearrange no numbers, did i do it right or not.
30. Use the Pythagorean Theorem: a^2 + b^2 = c^2
9^2 + 12^2 = c^2
81 + 144 = c^2
225 = c^2
square root of 225 = 15
33. Yes, you did this one right. :-)
Sure! Let's go through both problems step by step to find the correct answers.
30. To find the hypotenuse of a right triangle, you can use the Pythagorean theorem, which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. In this case, we have one side measuring 9 and another side measuring 12.
So, using the Pythagorean theorem, we can calculate the hypotenuse as follows:
c^2 = a^2 + b^2
Where c is the hypotenuse, and a and b are the other two sides.
Substituting the given values:
c^2 = 9^2 + 12^2
c^2 = 81 + 144
c^2 = 225
Now, to find the hypotenuse, we need to take the square root of both sides:
c = √225
c = 15
Therefore, the correct answer for the hypotenuse is 15, which means you got it right!
33. To find the median of a set of numbers, you need to arrange the numbers in ascending order and then determine the middle value. Let's work through this problem:
Given set of numbers: 2, 3, 5, 6, 10
To find the median, we first need to arrange the numbers in ascending order: 2, 3, 5, 6, 10.
Now, to determine the median, we need to find the middle value. Since we have an odd number of values (5 in total), the median will be the middle number.
In this case, the middle number is 5.
So, you were correct! The median of the given set of numbers is indeed 5.
I hope this helps! Let me know if you have any other questions or need further clarification.