When 20 grams of calcium carbonate decomposes, how many grams of calcium oxide are produced?

Two ways to do this, one short way and one long way.

Long way.
CaCO3 ==> CaO + CO2
mols CaCO3 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CaCO3 to mols CaO.
Then convert to g CaO. g CaO = mols CaO x molar mass CaO.

Short way.
20 g CaCO3 x (molar mass CaO/molar mass CaCO3) = ?g CaO.

The balanced chemical equation for the decomposition of calcium carbonate is:

CaCO3(s) → CaO(s) + CO2(g)

The molar mass of calcium carbonate (CaCO3) is calculated as follows:

1 calcium atom (Ca) = 40.08 g/mol
1 carbon atom (C) = 12.01 g/mol
3 oxygen atoms (O) = 3 * 16.00 g/mol

Adding up these molar masses, we find:

CaCO3 = 40.08 g/mol + 12.01 g/mol + (3 * 16.00 g/mol) = 100.09 g/mol

To find the grams of calcium oxide (CaO) produced from 20 grams of calcium carbonate, we need to use the molar ratio between CaCO3 and CaO from the balanced equation.

From the balanced equation, the molar ratio is 1:1, meaning 1 mole of CaCO3 produces 1 mole of CaO.

To find the moles of CaCO3, we divide the given mass by the molar mass:

Moles of CaCO3 = 20 g / 100.09 g/mol ≈ 0.1999 mol

Since the ratio between CaCO3 and CaO is 1:1, this means that 0.1999 mol of CaCO3 will produce 0.1999 mol of CaO.

Finally, to find the grams of CaO produced, we multiply the moles of CaO by its molar mass:

Grams of CaO = 0.1999 mol * 56.08 g/mol = 11.21 g

Therefore, when 20 grams of calcium carbonate decompose, approximately 11.21 grams of calcium oxide are produced.

To determine how many grams of calcium oxide are produced when 20 grams of calcium carbonate decomposes, we need to know the balanced chemical equation for the decomposition of calcium carbonate.

The chemical formula for calcium carbonate is CaCO3, and it decomposes into calcium oxide (CaO) and carbon dioxide (CO2) according to the following balanced chemical equation:

CaCO3 → CaO + CO2

From the equation, we can see that one molecule of calcium carbonate decomposes into one molecule of calcium oxide.

To calculate the number of grams of calcium oxide produced, we need to determine the molar mass of calcium oxide. The atomic masses of calcium (Ca) and oxygen (O) are 40.08 g/mol and 16.00 g/mol, respectively.

The molar mass of calcium oxide (CaO) is calculated as follows:

CaO = (Ca atomic mass) + (O atomic mass) = 40.08 g/mol + 16.00 g/mol = 56.08 g/mol

Now, we can calculate the number of moles of calcium oxide produced from 20 grams of calcium carbonate by using the molar mass and stoichiometry.

First, we calculate the molar mass of calcium carbonate (CaCO3):

CaCO3 = (Ca atomic mass) + (C atomic mass) + (3 * O atomic mass)
= 40.08 g/mol + 12.01 g/mol + (3 * 16.00 g/mol)
= 100.09 g/mol

Next, we calculate the number of moles of calcium carbonate using its molar mass and the given mass:

Number of moles = mass / molar mass
= 20 g / 100.09 g/mol
= 0.1999 mol (rounded to four decimal places)

Since the stoichiometry of the balanced equation shows that 1 mol of calcium carbonate produces 1 mol of calcium oxide, we can conclude that 0.1999 mol of calcium carbonate produces 0.1999 mol of calcium oxide.

Finally, we convert the moles of calcium oxide to grams by multiplying by the molar mass:

Mass of calcium oxide = number of moles * molar mass
= 0.1999 mol * 56.08 g/mol
= 11.2 g (rounded to one decimal place)

Therefore, when 20 grams of calcium carbonate decompose, approximately 11.2 grams of calcium oxide are produced.