salil travels 9km towards east then8km towards north and finally 7km towards east . how far away is he from his original place?
18 north east
so, a total of
16 east
8 north
Now just find the length of the hypotenuse.
To find the distance Salil is from his original place, we can use the Pythagorean theorem.
Step 1: Draw a diagram to represent Salil's movements. Start with an origin point (O) and mark the three directions he traveled: east (E), north (N), and east again (E).
7km 8km
E----N
| /
9km| /
| /
E
Step 2: Calculate the distances for the vertical and horizontal components. Salil traveled 9km east, 8km north, and 7km east.
Vertical distance (Y-axis): 8km
Horizontal distance (X-axis): 9km + 7km = 16km
Step 3: Use the Pythagorean theorem to find the diagonal distance (d) or the straight-line distance from Salil's original place to his final location.
d = sqrt(X^2 + Y^2)
= sqrt(16^2 + 8^2)
= sqrt(256 + 64)
= sqrt(320)
≈ 17.89km
Therefore, Salil is approximately 17.89km away from his original place.
To find out how far Salil is from his original place, we can visualize his movements on a coordinate plane.
1. Start by marking the origin as (0, 0).
2. Salil travels 9 km towards the east from the origin. This means he moves along the x-axis to the point (9, 0).
3. Next, Salil travels 8 km towards the north from the point (9, 0). This means he moves along the y-axis to the point (9, 8).
4. Finally, Salil travels 7 km towards the east from the point (9, 8). This means he moves along the x-axis to the point (16, 8).
Now, to calculate the distance between his final position and the origin, we can use the distance formula, which is based on the Pythagorean theorem:
distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, (x2, y2) is (16, 8), and (x1, y1) is the origin (0, 0).
Plugging the values into the formula:
distance = √((16 - 0)^2 + (8 - 0)^2)
= √(16^2 + 8^2)
= √(256 + 64)
= √320
≈ 17.89
Therefore, Salil is approximately 17.89 km away from his original place.