Electric bulb is Marked 60 watts 120 volt what is the resistance of filament of bulb
P = i V
60 = i (120)
i = .5 amps
V = i R
R =120/.5 = 240 Ohms
or
P = V^2/R
so
R = 120^2/60 = 240 Ohms
Well, I'm glad you asked. The resistance of the filament in a light bulb is quite shocking! Get ready for a bright idea. Using Ohm's Law, we can calculate the resistance (R) using the formula R = V^2 / P, where V is voltage (120 volts in this case) and P is power (60 watts). Plugging in the numbers, we get R = 120^2 / 60. So, grab your calculator and dim the lights because the resistance of the filament will be a dazzling 240 ohms!
To find the resistance of the filament in the electric bulb, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage (V) divided by the current (I):
R = V / I
In this case, the bulb is marked as 60 watts at 120 volts. We can use the power formula to find the current:
P = V * I
Rearranging the formula, we can express the current as:
I = P / V
Substituting the given values:
I = 60 watts / 120 volts
I = 0.5 Amperes
Now we can use Ohm's Law to find the resistance:
R = V / I
R = 120 volts / 0.5 Amperes
R = 240 Ohms
Therefore, the resistance of the filament in the bulb is 240 Ohms.
To find the resistance of the filament in the bulb, we can use Ohm's law. Ohm's law states that the resistance (R) is equal to the voltage (V) divided by the current (I). In this case, we have the power rating in watts (P) and the voltage (V).
First, we need to calculate the current (I). We can use the power formula, which states that power (P) is equal to the voltage (V) multiplied by the current (I). In this case, the power rating is given as 60 watts and the voltage is given as 120 volts.
Therefore, P = V × I
60 = 120 × I
Dividing both sides of the equation by 120, we get:
I = 60 / 120
I = 0.5 Amperes (A)
Now that we know the current, we can use Ohm's law to find the resistance (R). Ohm's law states that R = V / I, where V is the voltage and I is the current.
In this case, the voltage is given as 120 volts and the current is 0.5 Amperes.
Therefore, R = 120 / 0.5
R = 240 ohms
So, the resistance of the filament in the bulb is 240 ohms.