I have two numbers that have a sum of 16 and a difference of 3. By forming two equations and solving them find the two numbers.
X+Y=16___EQ1
X-Y=3____EQ2
2Y=13
Y=13/2
Y=6.5
Substitute Y=6.5 into EQ2
X-Y(6.5)=3
X-6.5=3
3+6.5=9.5
So:
X=9.5
Y=6.5
no
Well, it seems we have a mathematical dilemma here. Let's see if we can bring a little laughter to the equation!
Let's call the two numbers X and Y. According to your statement, we know that X + Y = 16 and X - Y = 3. Now, let's get silly and solve this!
We can solve this by adding the two equations together. When we do that, the Y terms will cancel out:
(X + Y) + (X - Y) = 16 + 3
2X = 19
Now, divide both sides by 2:
X = 19/2
Oh dear, we have a non-integer result. That's not very amusing, is it? But don't worry, let's not give up just yet.
Since X = 19/2, we can substitute it back into one of the equations to find Y:
(19/2) + Y = 16
Let's do some hilarious math:
Y = 16 - (19/2)
Now, let's solve this:
Y = 32/2 - 19/2
Y = (32 - 19)/2
Y = 13/2
So, based on these calculations, the two numbers are X = 19/2 and Y = 13/2.
Now, I know, I know... These results might not be what you were expecting, but hey, at least we tried to have fun along the way, right?
To solve this problem, we can set up a system of equations based on the given information.
Let's say the two numbers are x and y.
We are given two pieces of information:
1) The sum of the numbers is 16, so the equation is: x + y = 16.
2) The difference between the numbers is 3, so the equation is: x - y = 3.
Now, we have a system of equations:
Equation 1: x + y = 16
Equation 2: x - y = 3
To solve this system, we can use the method of substitution or elimination. Let's use the elimination method here:
Adding equation 1 and equation 2 eliminates the variable "y":
(x + y) + (x - y) = 16 + 3
2x = 19
Dividing both sides by 2, we get:
x = 19/2
x = 9.5
Now, substitute the value of x back into either equation to find the value of y. Let's use equation 1:
9.5 + y = 16
y = 16 - 9.5
y = 6.5
So, the two numbers are 9.5 and 6.5.
x+y=16
x-y=3
just add them, to find x
subtract them to get y
X= 16+3=19
Y= 16-3=13
X=19
Y=13