A particle of mass m1 = 2.5 kg moving along the x axis collides with a particle of mass m2 = 4.9 kg initially at rest. The incoming particle is deflected in the direction 22 degrees above the x axis, whereas the target particle moves off at 15 m/s at 37 degrees below the x axis. What are the initial and final speeds of the 2.5 kg particle?
I've tried this question at least 4 different ways and no matter what I do, I keep getting the same wrong answer. The last thing I did was a system of equations using the conservation of momentum equation, ΔP = P1 = P2, and the conservation of kinetic energy, ΔK = K1 = K2.
Also please hurry this is due tonight!!
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2 answers

No one said energy was conserved!!!!
Momentum is conserved in the x direction
AND
Momentum is conserved in the y direction 👍
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answered by Anonymous 
Initial x momentum = 2.5 u
Initial y momentum = 0
Final x momentum = 2.5 V cos 22 + 4.9 (15) cos 37
Final y momentum = 2.5 V sin 22  4.9(15)sin 37
SO
use final y momentum = 0 to get velocity of particle 2
4.9(15) sin 37 = 2.5 V sin 22
then go back and use the x momentum to get u, the initial speed 👍
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answered by Anonymous
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