Ask questions and get helpful answers.

A particle of mass m1 = 2.5 kg moving along the x axis collides with a particle of mass m2 = 4.9 kg initially at rest. The incoming particle is deflected in the direction 22 degrees above the x axis, whereas the target particle moves off at 15 m/s at 37 degrees below the x axis. What are the initial and final speeds of the 2.5 kg particle?

I've tried this question at least 4 different ways and no matter what I do, I keep getting the same wrong answer. The last thing I did was a system of equations using the conservation of momentum equation, ΔP = P1 = P2, and the conservation of kinetic energy, ΔK = K1 = K2.

Also please hurry this is due tonight!!

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

2 answers

  1. No one said energy was conserved!!!!

    Momentum is conserved in the x direction
    AND
    Momentum is conserved in the y direction

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Initial x momentum = 2.5 u
    Initial y momentum = 0

    Final x momentum = 2.5 V cos 22 + 4.9 (15) cos 37

    Final y momentum = 2.5 V sin 22 - 4.9(15)sin 37

    SO

    use final y momentum = 0 to get velocity of particle 2

    4.9(15) sin 37 = 2.5 V sin 22

    then go back and use the x momentum to get u, the initial speed

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.