Two buses leave a bus station and travel in opposite direction from the same standing point.if the speed of one is twice the other and they are 240km apart at the end of one hour. What is the speed of each km
V1 = Speed of 1st bus.
V2 = 2V1 = Speed of 2nd bus.
d1 + d2 = 240.
V1*t + 2V1*t = 240,
3V1*t = 240,
3V1*1 = 240, V1 = 80 km/h.
V2 = 2V1 = 2*80 = 160 km/h.
Is this correct
correct
To determine the speeds of each bus, let's assign variables to represent their speeds.
Let's say the speed of the first bus is "x" km/h. According to the problem, the second bus's speed is twice that, so the speed of the second bus would be "2x" km/h.
Since they are traveling in opposite directions, their speeds will add up. Therefore, the combined speed of the two buses can be represented as "x + 2x", which simplifies to "3x" km/h.
The problem states that they are 240 km apart at the end of one hour. Distance equals speed multiplied by time. So, the equation can be written as:
240 = (3x) * 1
To solve for "x," divide both sides of the equation by 3:
240 / 3 = x
80 = x
Therefore, the speed of the first bus, x, is 80 km/h, and the speed of the second bus, which is twice the first bus's speed, is 2 * 80 = 160 km/h.
So, the speed of the first bus is 80 km/h, and the speed of the second bus is 160 km/h.