rearrange A = 2 pi r (r+h) to make h the subject

(cylinder)

A = 2 pi r (r+h)

A = 2π r^2 + 2πrh
A - 2πr^2 = 2πrh
h = (A - 2πr^2)/(2πr)

To rearrange the formula A = 2πr(r+h) to make h the subject, we need to isolate the variable h.

Step 1: Expand the formula
A = 2πr(r+h)
A = 2πr^2 + 2πrh

Step 2: Move the term 2πr^2 to the other side of the equation
2πr^2 = A - 2πrh

Step 3: Divide both sides of the equation by 2πr
2πr^2 / (2πr) = (A - 2πrh) / (2πr)

Simplifying:
r = (A - 2πrh) / (2πr)

Step 4: Multiply both sides of the equation by (2πr)
r * (2πr) = (A - 2πrh)

Simplifying:
2πr^2 = A - 2πrh

Step 5: Add 2πrh to both sides of the equation
2πrh + 2πrh = A

Simplifying:
4πrh = A

Step 6: Divide both sides of the equation by 4πr
4πrh / (4πr) = A / (4πr)

Simplifying:
h = A / (4πr)

Therefore, h = A / (4πr)

To rearrange the equation A = 2πr(r + h) to make h the subject, follow these steps:

Step 1: Expand the equation.
A = 2πr² + 2πrh

Step 2: Move the term with h to one side of the equation.
A - 2πr² = 2πrh

Step 3: Divide both sides of the equation by 2πr to isolate h.
(A - 2πr²) / (2πr) = h

Now h is the subject of the equation.

S=2pir(r+h)