10. a rectangle has width the same as a side of a square whose perimeter is 20m. the length of the rectangle is 9m. find the perimeter of this rectangle.
34. The width of a rectangular picture is one-half the length. The perimeter of the rectangle is 72 inches. Find the length of the picture.
35. The width of a rectangular playground is 18 meters less than the length. Find the width when the perimeter of the rectangle is 84meters.
33. Translate to an algrebraic equation then solve.
The length of rentagle is six units longer than the width. find the length and width if the perimeter of the rectangle is 60 units.
36. The legth of a rectangle is three times the width . The perimeter is 49 units . Find the length.
37. The perimeter of a rectangle carpet is 70 feet. The width is three- fourths the length . Find the width.
38. The lenght of a rectangulat room is six times as the width . The perimeter is 84 yards. Find the width.
39. The width of a rectangle is 12 units less than the length . The perimeter is 108 units . Find the length.
40. The lenght of a rectangular picutre is seven inches longer than the width . Find the length and the width if the perimeter of the picture is 62.
When I was still teaching, I used to have my students write down the English sentence, and then below it have it translated into "math".
example: # 36
The length of a rectangle is three times the width
l= 3w
The perimeter is 49 units
2l + 2w = 49 but l=3w
so 2(3w)+2w=49
8w=49
w=49/8
most of the others can be done is such a way.
Good Post, Reiny.
The perimeter of a rectangle carpet is 70 feet. The width is three- fourths the length . Find the width.
wow this is a awkward post lol
Step 1: Write down the given information:
Perimeter of the rectangle = 70 feet
Width = three-fourths the length
Step 2: Translate the information into mathematical equations:
Let's assume the length of the rectangle as "L".
According to the given information, the width (W) can be expressed as:
Width = (3/4) * Length
Step 3: Use the formula for the perimeter of a rectangle:
Perimeter of a rectangle = 2 * (Length + Width)
Substituting the given values:
70 = 2 * (L + (3/4) * L)
Step 4: Simplify the equation:
70 = 2 * (L + (3/4) * L)
70 = 2 * (4/4 * L + 3/4 * L)
70 = 2 * (7/4 * L)
Step 5: Multiply both sides of the equation by (2/7) to solve for L:
70 * (2/7) = 2 * L
20 = L
Step 6: Calculate the width:
Width = (3/4) * Length
Width = (3/4) * 20
Width = 15 feet
Therefore, the width of the rectangle is 15 feet.
To find the width of the rectangle carpet, we can start by translating the information given into an algebraic equation.
Let's use the letter "w" to represent the width of the rectangle carpet and "l" to represent the length.
According to the information given, the width is three-fourths the length. This can be written as:
w = (3/4)l
We also know that the perimeter of the rectangle carpet is 70 feet. The formula for the perimeter of a rectangle is:
perimeter = 2(length + width)
In this case, the perimeter is given as 70 feet, so we can set up the equation:
70 = 2(l + w)
Now we can substitute the value of "w" from the first equation into the second equation:
70 = 2(l + (3/4)l)
Simplifying the equation further, we have:
70 = 2(7/4)l
Multiplying 2 by (7/4) gives us:
70 = (14/4)l
Simplifying the right side of the equation, we have:
70 = (7/2)l
To isolate "l," we can divide both sides of the equation by (7/2):
(70) / (7/2) = l
Simplifying the right side by multiplying the numerator by the reciprocal of the denominator:
(70) * (2/7) = l
We find that:
l = 20
So the length of the rectangle carpet is 20 feet.
Now that we know the length, we can substitute it back into the first equation to find the width:
w = (3/4)(20)
Simplifying the right side:
w = 15
Therefore, the width of the rectangle carpet is 15 feet.