How many 3-digit numbers can be formed using the digits 1, 2, 3, 4, 5, 6, 7 if repetition of digits is not allowed?

There are 7 choices for first digit, 6 for second and 5 for third digit. So, there can be 7x6x5=210 3-digit numbers.

Well, let's do a bit of number crunching! Since there are 7 digits to choose from, we can say there are 7 options for the first digit, 6 options for the second digit (because repetition is not allowed), and 5 options for the third digit. So, the total number of 3-digit numbers would be 7 * 6 * 5 = 210. That's a lot of numbers that can be formed. Just don't tell them any knock-knock jokes, numbers tend to be a little square and don't always appreciate the humor!

To find the number of 3-digit numbers that can be formed using the digits 1, 2, 3, 4, 5, 6, and 7 without repetition, we can use the concept of permutations.

Since repetition is not allowed, the first digit can be chosen from any of the 7 available digits (1, 2, 3, 4, 5, 6, or 7). Once the first digit is chosen, there are 6 remaining digits to choose from for the second digit. Finally, there are 5 remaining digits to choose from for the third digit.

Therefore, the total number of 3-digit numbers that can be formed is given by:
7 * 6 * 5 = 210

So, there are 210 3-digit numbers that can be formed using the given digits without repetition.

To find out how many 3-digit numbers can be formed using the given digits without repetition, we can use the concept of permutations.

Since there are 7 digits to choose from (1, 2, 3, 4, 5, 6, 7) and we need to form a 3-digit number, the first digit can be chosen in 7 ways. After choosing the first digit, the second digit can be chosen in 6 ways (as repetition is not allowed), and the third digit can be chosen in 5 ways.

To find the total number of possibilities, we multiply the number of choices for each digit: 7 * 6 * 5 = 210.

Therefore, there are 210 different 3-digit numbers that can be formed using the digits 1, 2, 3, 4, 5, 6, 7 without repetition.