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A 0.4550g solid mixture containing CaSO4 dissolved in water and treated with an excess of Ba(NO3)2, resulting in precipitation of 0.6168g of BaSO4. What is the concentration ( weight percent) of CaSO4 in the mixture?

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  2. g CaSO4 = 0.0.6168 x (molar mass CaSO4/molar mass BaSO4) = ?
    Then % CaSO4 = (g CaSO4/mass sample)*100 = ?
    mass of sample is 0.4550g

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