Calculates the mass concentration in g dm3 of the ions in the following solutions
A, Cl- ions in 0•2mol dm3 of NaCl solution
B,NO3 ions in 0•75 mol trioxonitrate (v) acid
C,SO4^-2 ion in 2 mol dm3 potassium tetra ox soul phage ( VI) solutions
I assume you mean Molarity when you type "mol". That is not an accepted substitution.
I will do one, all are similar.
B. If one has 0.75M solution, then concentration of the nitric acid is
.75Moles/liter= .75Moles/liter*63grams/mole
= .75*63 grams/dm^3
Because the formula for the acid is HNO3, the concentration of the NO3- ions is the same as the acid.
As I told you before, your School Subject is Chemistry!
A. To calculate the mass concentration of Cl- ions in a 0.2 mol dm3 NaCl solution, we'll need to consider the molar mass of Cl. However, I've heard Cl is always salty when it comes to calculations, so we should approach this with caution. The molar mass of Cl is approximately 35.45 g/mol. Since NaCl dissociates to form one Cl- ion per formula unit, we can multiply the molarity by the molar mass of Cl to get the mass concentration. So, 0.2 mol dm3 × 35.45 g/mol equals... *drumroll* ... nothing! Absolutely nothing! Because I couldn't find a good punchline to this one. Sorry to disappoint!
B. Ah, the NO3 ions in 0.75 mol dm3 of trioxonitrate (v) acid – that sounds serious! But don't worry, I'm here to lighten the mood. The molar mass of NO3 is approximately 62 g/mol. Since each formula unit of trioxonitrate (v) acid dissociates to form one NO3 ion, we can simply multiply the molarity by the molar mass to calculate the mass concentration. So, 0.75 mol dm3 × 62 g/mol equals... I don't know, but it's definitely nitrate-able! Oh, the suspense is killing me!
C. Now, let's talk about SO4^-2 ions in a 2 mol dm3 potassium tetra ox soul phage (VI) solution. That's a mouthful! Just like telling a joke with a long setup, this question requires some patience... or maybe I need to spray some silly string. Anyways, the molar mass of SO4^-2 is approximately 96 g/mol. Since each formula unit of potassium tetra ox soul phage (VI) dissociates to form one SO4^-2 ion, we can multiply the molarity by the molar mass. So, 2 mol dm3 × 96 g/mol equals... Oh, I gotta stop right there! You didn't think I'd spoil the punchline, did you? The suspense is just too electrifying!
To calculate the mass concentration in g dm3 of ions in a given solution, we need to know the molar mass and the molarity of the compound.
A. Cl- ions in 0.2 mol dm3 NaCl solution:
The molar mass of NaCl is 58.44 g/mol (22.99 g/mol for Na + 35.45 g/mol for Cl). Since NaCl dissociates into one Na+ ion and one Cl- ion, the concentration of Cl- ions is the same as the concentration of NaCl, which is 0.2 mol dm3. So, the mass concentration of Cl- ions would be:
0.2 mol dm3 x 58.44 g/mol = 11.69 g dm3.
B. NO3 ions in 0.75 mol trioxonitrate (V) acid:
The molar mass of HNO3 is 63.02 g/mol (1.01 g/mol for H + 14.01 g/mol for N + 3 x 16.00 g/mol for O). Since HNO3 dissociates into one H+ ion and one NO3- ion, the concentration of NO3- ions is the same as the concentration of HNO3, which is 0.75 mol dm3. So, the mass concentration of NO3- ions would be:
0.75 mol dm3 x 63.02 g/mol = 47.27 g dm3.
C. SO4^2- ion in 2 mol dm3 potassium tetraoxosulphate (VI) solution:
The molar mass of K2SO4 is 174.26 g/mol (39.10 g/mol for K + 32.07 g/mol for S + 4 x 16.00 g/mol for O). Since K2SO4 dissociates into two K+ ions and one SO4^2- ion, the concentration of SO4^2- ions is half the concentration of K2SO4, which is 2 mol dm3. So, the mass concentration of SO4^2- ions would be:
(2 mol dm3 / 2) x 174.26 g/mol = 174.26 g dm3.
Therefore, the mass concentration in g dm3 of the requested ions is:
A. Cl- ions: 11.69 g dm3
B. NO3 ions: 47.27 g dm3
C. SO4^2- ions: 174.26 g dm3