What is the centripetal acceleration of an automobile driving at 40 km/h on a circular track of radius 20m?
Help ASAP please!!!
as u know........... centripetal acc=V2/r............... but we have to change the unit of velocity in order to get answer in S.I unit ok........................... so 40 x 1000/3600=11.11m/sec now ac=V2/r.... (11.11)2/20=6.172m/sec2
To calculate the centripetal acceleration of an object moving in a circular path, you can use the formula:
a = v^2 / r
where:
a = centripetal acceleration
v = velocity of the automobile
r = radius of the circular track
First, let's convert the velocity from km/h to m/s.
1 km/h = 1000 m/3600 s
40 km/h = (40 * 1000 m) / 3600 s = 40000 m / 3600 s
40 km/h = 40/3.6 m/s (rounded to two decimal places)
Therefore, the velocity of the automobile is 11.11 m/s (rounded to two decimal places).
Now, we can substitute the values into the formula:
a = (11.11 m/s)^2 / 20 m
a = 123.21 m^2/s^2 / 20 m
a = 6.16 m/s^2
Therefore, the centripetal acceleration of the automobile driving at 40 km/h on a circular track of radius 20m is 6.16 m/s^2.
To calculate the centripetal acceleration of an object moving in a circular path, you can use the formula:
a = v^2 / r
Where:
a = centripetal acceleration
v = velocity
r = radius of the circular path
In this case, the velocity is given as 40 km/h, and it needs to be converted to meters per second (m/s) because the SI unit system is used in the formula. To convert km/h to m/s, divide the velocity by 3.6:
40 km/h ÷ 3.6 = 11.11 m/s (rounded to two decimal places)
Now that we have the velocity, we can substitute the values into the formula:
a = (11.11 m/s)^2 / 20 m
Simplifying further:
a = 123.21 m^2/s^2 / 20 m
a ≈ 6.16 m/s^2
Therefore, the centripetal acceleration of the automobile driving at 40 km/h on a circular track with a radius of 20m is approximately 6.16 m/s^2.