The initial speed of a body is 4.43 m/s. What is its speed after 1.86 s if it accelerates uniformly at 1.24 m/s^2? Answer in units of m/s. PLz help
Forgot this part: What is its speed after 1.86 s if it accelerates
uniformly at −1.24 m/s^2? Answer in units of m/s.
v = vo + at
now just plug in your numbers.
The speed changes by 1.24 m/s every second.
To find the final speed of the body, we can use the formula:
v = u + at
where:
v is the final speed,
u is the initial speed,
a is the acceleration, and
t is the time.
Given:
u = 4.43 m/s
a = 1.24 m/s^2
t = 1.86 s
Substituting the given values into the formula, we have:
v = 4.43 m/s + (1.24 m/s^2) * (1.86 s)
v = 4.43 m/s + 2.3024 m/s
v ≈ 6.73 m/s
Therefore, the speed of the body after 1.86 seconds is approximately 6.73 m/s.
To find the final speed of the body, we can use the following equation:
v = u + at
Where:
v = final velocity (speed)
u = initial velocity (speed)
a = acceleration
t = time
In this case, the initial speed of the body is u = 4.43 m/s, the acceleration is a = 1.24 m/s^2, and the time is t = 1.86 s.
Plugging in these values into the equation, we get:
v = 4.43 m/s + (1.24 m/s^2)(1.86 s)
Now, let's calculate the result:
v = 4.43 m/s + (1.24 m/s^2)(1.86 s)
v = 4.43 m/s + 2.3024 m/s
v = 6.7324 m/s
Therefore, the speed of the body after 1.86 seconds is approximately 6.7324 m/s.