A bus and a car leave the same place and travel in opposite directions. If the bus is traveling at 50 mph and the car is traveling at 55 mph, in how many hpurs will they be 210 miles apart.

Again please help me with the boxes, Im in advanced math and I'm not good with the boxes...

To solve this problem, you can use the concept of relative speed. When two objects are moving in opposite directions, their distances are increasing at the sum of their speeds.

In this case, the bus is traveling at 50 mph and the car is traveling at 55 mph. So, the relative speed between the bus and the car is 50 mph + 55 mph = 105 mph. This means that the distance between the bus and the car is increasing at a rate of 105 miles per hour.

To find out how long it takes for them to be 210 miles apart, you can divide the distance by the relative speed:

Time = Distance / Speed

Time = 210 miles / 105 mph

Time = 2 hours

So, in 2 hours, the bus and the car will be 210 miles apart.

Regarding your mention of "boxes," it seems like a formatting issue. The problem can be solved without the use of boxes. However, if you need help with organizing your solution or using a specific method, please let me know, and I'll be happy to assist you further.

Boxes?

The have a relative veloicty of 105, and cover a distance of 210mi.

time=distance/velocity

I have no idea what "boxes" means here.

A bus travels at 90km/h. how far will it have traveled after 210 minutes?

Very similar to the other one I showed you

for your bus columns:
distance = x miles
rate = 50 mph
time = x/50 hours

for your car columns:
distance = 210-x miles
rate = 55 mph
time = (210-x)/55 hours

Don't both of them travel for the same period of time ??
so .. x/50 = (210-x)/55
cross-multiply and solve