An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that
travel 1530 m/s in seawater.
How deep is the water directly below the vessel if the time delay of the echo to the ocean floor and back is 7 s? Answer in units of m. Is it 1530*7?
the delay time is down and back ... twice the depth
so it's 1530*14?
No, it takes 7 seconds to make the round trip.
Stop guessing and start calculating.
i think the answer is 5355m
That's better
To determine the depth of the water directly below the vessel, we need to calculate the round-trip distance traveled by the ultrasonic wave.
The speed of sound in seawater is given as 1530 m/s. Since the round-trip time delay of the echo is 7 s, we divide this time by 2 to get the one-way travel time.
One-way travel time = 7 s / 2 = 3.5 s
To find the distance traveled, we multiply the speed of sound by the one-way travel time:
Distance = Speed × Time
Distance = 1530 m/s × 3.5 s
Now we can calculate the depth of the water directly below the vessel. Since the acoustic wave travels from the vessel to the ocean floor and back, the depth is half of the total distance traveled:
Depth = (1530 m/s × 3.5 s) / 2
Evaluating this expression will give us the answer in units of meters.