THE BASE OF A TRIANGLE IS 3CM LONGER THAN ITS CORRESPONDING HEIGHT. IFTHE AREA IS 44CM^2. FIND THE LENGTH OF ITS BASE

h(h+3)/2=44

8cm

I don't think this is the right answer

To find the length of the base of the triangle, we can use the formula for the area of a triangle:

Area = (1/2) * base * height

Given that the base is 3 cm longer than the corresponding height, we can represent the length of the height as 'x' cm. Therefore, the length of the base would be 'x + 3' cm.

We are also given that the area is 44 cm^2. Substituting these values into the formula, we get:

44 = (1/2) * (x + 3) * x

Now we can solve this equation to find the length of the base 'x + 3'.

Multiplying both sides by 2 to eliminate the fraction, we have:

88 = (x + 3) * x

Expanding the equation, we get:

88 = x^2 + 3x

Rearranging the equation, we have:

x^2 + 3x - 88 = 0

Now we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula.

Factoring gives us:

(x + 11)(x - 8) = 0

Setting each factor equal to zero, we have:

x + 11 = 0 or x - 8 = 0

Solving these equations gives us:

x = -11 or x = 8

Since the length cannot be negative, we can discard the solution x = -11.

Therefore, the length of the height is 8 cm.

Substituting this value back into the expression for the base, we get:

Base = x + 3 = 8 + 3 = 11 cm

Therefore, the length of the base of the triangle is 11 cm.

A

1/2(h+3)h