a bullet of mass 0.03kg enters a block of wood with a velocity 600m/s & penatrate to a depth of 0.2m .Calculate the average force of the wood to the penetration of the bullet

change of momentum = .03*600 = 18

average speed = 300
time = .2/300

Force = change of momentum/change of time
= 18 *300/.2 Newtons
= 90*300
=27,000 agree

27000

Thanks sir

To calculate the average force of the wood on the bullet, we can make use of the concept of impulse. Impulse is defined as the change in momentum of an object and is equal to the force applied over a period of time.

Here's how to calculate the average force using the given values:

1. Calculate the initial momentum (p1) of the bullet before penetrating the wood. Momentum (p) is given by the formula p = mass (m) × velocity (v).
p1 = m × v
p1 = 0.03 kg × 600 m/s

2. Calculate the final momentum (p2) of the bullet after penetrating the wood. Since the bullet comes to rest, the final momentum is zero.
p2 = 0 kg × 0 m/s
p2 = 0

3. Calculate the change in momentum (∆p) of the bullet by subtracting the final momentum from the initial momentum.
∆p = p2 - p1
∆p = 0 - (0.03 kg × 600 m/s)

4. The change in momentum (∆p) is equal to the impulse (J) applied to the bullet during penetration. Impulse is given by the formula J = ∆p.
J = ∆p = (0.03 kg × 600 m/s)

5. The impulse (J) is equal to the average force (F) multiplied by the time (Δt) over which the force is applied. Since the time is not given in the question, we assume that it is the same as the time taken for the bullet to penetrate the wood. We can calculate the time (Δt) using the formula Δt = distance (d) / velocity (v).
Δt = 0.2 m / 600 m/s

6. Substitute the impulse (J) and the time (Δt) into the formula F = J / Δt to calculate the average force.
F = J / Δt
F = (0.03 kg × 600 m/s) / (0.2 m / 600 m/s)

Now, you can calculate the average force exerted by the wood on the bullet by performing the above calculations.

60000