A soccer ball accelerates from rest and rolls 6.5 m down a hill in 3.1 s. It then bumps into a tree. What is the speed of the ball just before it hits the tree?

A formula to answer this question would be fine; you don't have to solve the whole thing.

the ball is uniformly accelerated by gravity

average velocity =
... (final vel. + initial vel.) / 2

6.5 m / 3.1 s = (V fin + 0) / 2

okboi

answer is 2.09

wait whats the answer?

Well, it seems like the soccer ball had quite a downhill adventure! To find the speed of the ball just before it hits the tree, we can use the formula for average speed:

Average Speed = Distance / Time

However, since the ball accelerated from rest, we need to find its average speed over the entire 6.5 m distance. To find the final speed just before hitting the tree, we'll need to consider the ball's acceleration as well. Good luck with the calculations!

To find the speed of the soccer ball just before it hits the tree, we need to calculate its final velocity (speed) using the formula for uniformly accelerated motion.

The formula for uniformly accelerated motion is:
v = u + at

Where:
v = final velocity
u = initial velocity (in this case, the ball starts from rest, so its initial velocity is zero)
a = acceleration
t = time

Since the ball is rolling down a hill, it experiences an acceleration due to gravity, which is approximately 9.8 m/s^2. The time taken to roll down the hill is given as 3.1 seconds.

Using the formula, we can find the final velocity (v) before it hits the tree.

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