
U={80}
5 more than twice of the number of hockey players plays football.
Let the hockey players(H) be X
Football players(F) be 2X+5
To find X
2X+5=FnH'+15. Equation1 X=HnF'+15. Equation2
80=(2X+515)+15+(X15)
X=30
From here substitute X into equation1 and 2 to get F only nd H only
And remember that F will become 2(30)+5=65

solve it for me

To get x = 30 just add the number of two games and the no that play both and equate it to no of the student, and no of the student is 80
X15+15+(2x+5)15=80
X+2x+515=80
3x10=80
3x=80+10
3x=90
X=30
To find no. (ii) and (iii)
ii. n(F)only= total no of F none
And total no of F is 2x+5
=2(30)+5
=65
Therefore, n(F)only=6515 =50
iii. n(H)only = total no of H  none
And total no of H is x which is 30
Therefore, n(H)only=3015
=15

In a senior secondary school, 80 students play hockey or football. The number that play football is 5 more than twice the number that play hockey. If the 15 students play both games and every student in the school playsat least one game, find:
The number of students that play football;
The number of students that play football but not hockey;
The number of students that play hockey but not football. Full working sir

number who play hockey  x
number who play football  2x+5
x + 2x+5 = 80
x = 25
so 25 play hockey, 55 play football, and 15 play both
now we can use a Venn diagram, filling in as follows:
15 in the intersection
5515 or 40 in the football only part of the circle
2515 or 10 in the hockey only part of the circle
All your questions can now be easily answered.

pls i really need the working and answer,can u help me with it

H=x
F=5+2x
Therefore, x+5+2x+15=80
3x+20=80
3x=60
X=20
Proof: x+5+2x+15
20+5+40+15=80

I don't get what reiny is trying to say

In the department of mathematics, unilag, 80 students play hockey or football. The number that play football is 5 more than twice the number that play hockey. If 15 students play both games and every student in school plates at least one game. Find the number of students that play football but not hockey

I got lost on Alexander explanation starting from how to get x

this maths is confusing especially on how to get the number of those who played football when hockey is 5 and hockey only is 20. i.e H=5+2x+15+x=80. 5+15+2x+x=80 20+3x=80 3x=8020 3x=60 hockey only=20 hockey=2015 =5

D response I'm getin isn't helpin .d ansa from alexandra nd anonymous ren't same.wich should I chose x=20 or x=30

Equation on number of students that play football only

Total number of student =80
N(F n H)=15
N(F)=5+2x
N(H)=x
(I). The number that play football
To get that , we need to sum up all the n( F) and n(H) to 80
I.e 5+2x15 +15+X15=80
3x10=80
3x=90
X=30
Therefore; n(F)=5+2x
=5+60=65.
(ii). The number that play football but not hockey
N(F n H')
To get that we need to subtract the intercept from the to ta number that play football .and the intercept is 15
Therefore; 6515=50
(ii). The number that play hockey but not football
N(F' n H)
We already know that x =30 and the intercept is 15
Therefore ; 3015=15.

The number of those that played football but not hokey

This was so helpful