The perimeter of a rectangle is 80 in. The length is 6 inches more than the width. What are the dimensions of the rectangle

p = 2L + 2W

80 = 2(W + 6) + 2W

80 = 4W + 12

68 = 4W

17 = W

Let's call the width of the rectangle "W" inches.

According to the given information, the length of the rectangle is 6 inches more than the width. So, the length would be "W + 6" inches.

The formula for calculating the perimeter of a rectangle is: Perimeter = 2 * (length + width)

Substituting the given information into the formula, we have:

80 = 2 * ((W + 6) + W)

Simplifying the equation:

80 = 2 * (2W + 6)

Dividing both sides of the equation by 2:

40 = 2W + 6

Subtracting 6 from both sides of the equation:

34 = 2W

Dividing both sides of the equation by 2:

17 = W

Now, let's substitute the value of W back into the equation to find the length of the rectangle:

Length = W + 6 = 17 + 6 = 23 inches

So, the dimensions of the rectangle are:
Width = 17 inches
Length = 23 inches

To find the dimensions of the rectangle, we need to set up equations using the given information.

Let's assume the width of the rectangle is represented by "w" inches.
According to the problem, the length is 6 inches more than the width, so the length would be "w + 6" inches.

The formula for the perimeter of a rectangle is given by:
Perimeter = 2 × (length + width)

Given that the perimeter is 80 inches, we can set up the equation as follows:

80 = 2 × (w + (w + 6))

Simplifying the equation, we get:

80 = 2 × (2w + 6)

Now, we can solve for "w":

80 = 4w + 12

Rearranging the equation:

4w = 80 - 12
4w = 68

Dividing by 4 on both sides:

w = 68 / 4
w = 17

So, the width of the rectangle is 17 inches.

To find the length, we can substitute the value of "w" into the equation for the length:

Length = w + 6
Length = 17 + 6
Length = 23

Therefore, the dimensions of the rectangle are:
Width: 17 inches
Length: 23 inches