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a stone is thrown vertically upward an initial velocity of 12m/s from the top of a building . it takes 3.4s for the stone to hit the ground

a. find the height of the building
b. find the maximum height that the stone will reach
c. find the speed of the stone when it reaches the ground

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2 answers
  1. the free-fall equation is
    ... h = -4.9 t^2 + 12 t + Hb

    a. 0 = -4.9(3.4)^2 + 12(3.4) + Hb

    b. Tmax = -12 / (2 * -4.9)
    ... plug Tmax into the free-fall equation to find Hmax

    c. v = g(3.4 - Tmax)

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