The mass of an empty container is 91 g. The
mass of the container filled with water is 111 g.
What is the volume of the container? The
density of water is 1 g/cm3
.Answer in units of cm3
20cm3
016 (part 2 of 5) 1.0 points
The container was emptied, dried, and a piece
of metal added to give a total mass of the
container and metal of 161 g. What is the
mass of the metal added to the container?
Answer in units of g.
70g
017 (part 3 of 5) 1.0 points
The container with the metal in it was filled
with water. The total mass of the container,
metal, and water was 171 g. What is the mass
of the water added to the container?
Answer in units of g.
10g
018 (part 4 of 5) 1.0 points
What is the volume of the water added to the
container with the metal still in the container?
Answer in units of cm3
??
019 (part 5 of 5) 1.0 points
What is the density of the metal?
Answer in units of g/cm3
??
The mass of an empty container is 91 g. The
mass of the container filled with water is 111 g.
What is the volume of the container? The
density of water is 1 g/cm3
.Answer in units of cm3
20cm3
right
016 (part 2 of 5) 1.0 points
The container was emptied, dried, and a piece
of metal added to give a total mass of the
container and metal of 161 g. What is the
mass of the metal added to the container?
Answer in units of g.
70g
right
017 (part 3 of 5) 1.0 points
The container with the metal in it was filled
with water. The total mass of the container,
metal, and water was 171 g. What is the mass
of the water added to the container?
Answer in units of g.
10g
right
018 (part 4 of 5) 1.0 points
What is the volume of the water added to the
container with the metal still in the container?
Answer in units of cm3
??
mass = volume x density.
mass H2O = 10 g
density H2O = 1.0 g/cc
volume = ? g/cc
019 (part 5 of 5) 1.0 points
What is the density of the metal?
Answer in units of g/cm3
??
mass = volume x density
mass metal = 70 g
volume metal = volume water displaced = 10 cc
density metal = mass/volume = ? g/cc.
To find the volume of water added to the container with the metal still in it, we need to calculate the difference in mass before and after the water was added.
The mass of the container filled with water is given as 111 g, and the total mass of the container, metal, and water is given as 171 g.
So, the mass of the water added to the container is:
Mass of water = Total mass - Mass of container
= 171 g - 111 g
= 60 g
To find the volume of water added, we can use the density of water, which is 1 g/cm³.
So, the volume of water added is:
Volume of water = Mass of water / Density of water
= 60 g / 1 g/cm³
= 60 cm³
Therefore, the volume of water added to the container with the metal still in it is 60 cm³.
Next, to find the density of the metal, we can use the mass of the metal added and the volume of the metal.
The mass of the metal added to the container is given as 70 g.
Now, to find the volume of the metal, we need to calculate the difference in mass of the container and metal before and after the metal was added.
The mass of the container filled with water and metal is given as 161 g, and the mass of the empty container is given as 91 g.
So, the mass of the metal is:
Mass of metal = Total mass - Mass of container
= 161 g - 91 g
= 70 g
Since the mass of the metal is the same as the mass of the metal added, the volume of the metal added is equal to the volume of the metal in the container, which is the volume of the water added.
Therefore, the volume of the metal is 60 cm³.
Finally, to find the density of the metal, we can use the formula:
Density = Mass / Volume
Density of the metal = Mass of the metal / Volume of the metal
= 70 g / 60 cm³
= 1.17 g/cm³
Therefore, the density of the metal is approximately 1.17 g/cm³.
To find the volume of the water added to the container with the metal still in it, we need to determine the difference in mass before and after adding the water. Here are the steps to calculate it:
1. Start with the mass of the container, metal, and water: 171 g.
2. Subtract the mass of the container and metal (161 g) to find the mass of the water added: 171 g - 161 g = 10 g.
3. The mass of the water added is equal to its volume because the density of water is 1 g/cm³.
Therefore, the volume of the water added to the container with the metal is 10 cm³.
To find the density of the metal, we can use the information given:
1. Start with the mass of the metal added to the container: 70 g.
2. The density of a substance is given by the formula: density = mass / volume.
3. We already know the mass of the metal (70 g), but we need to find its volume.
4. The volume of the metal can be obtained by finding the difference in volume before and after adding the metal to the container.
a. Before adding the metal, the volume of the container was determined to be 20 cm³.
b. After adding the metal, the volume of the container remains the same because we assume the metal does not displace any water.
c. Therefore, the volume of the metal is also 20 cm³.
5. Substituting the values in the formula: density = 70 g / 20 cm³ = 3.5 g/cm³.
Therefore, the density of the metal is 3.5 g/cm³.