Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Trigonometry
Inverse Trigonometric Functions
what is the appropriate approximation of cot^-1 27
1 answer
cot^-1 27 is the angle Ø so that cotØ = 27
or
tanØ = 1/27
my calculator gives me appr 2.12°
You can
ask a new question
or
answer this question
.
Similar Questions
Justin wants to evaluate 3cot(-5pi/4). Which of the following identities can he use to help him? Select two answers.
cot(-theta)
Top answer:
for honors: 1. D (4pi) 2. B, D (cot(-θ)=-cot(θ)), (cot(θ+pi)=cot(θ) 3. A, B (f(x)=csc x),
Read more.
1)if the graph of f(x)=cotx is transformed by a horizontal shrink of 1/4 and a horizontal shift left pi, the result is the graph
Top answer:
The standard cotangent function y = cot x has a period of π radians , or form 0 to π there will be
Read more.
A right triangle has acute angles C and D. If tan C=158 and cos D=1517, what are cot D and sin C?
cot D=8/15 and sin C=8/17 cot
Top answer:
I labelled the triangle CDE, with E as the right angle. All you have to do is recognize that your
Read more.
Algebraically find the value of: 10 cot(cot^(-1)3+cot^(-1)7+cot^(-1)13+cot^(-1)21 )
Top answer:
Take a look here: http://www.maths.surrey.ac.uk/hosted-sites/R.Knott/Fibonacci/fibpi.html and scroll
Read more.
Use implicit differentiation to show
dy/dx = [(1-xy)cot(y)]/[x^2 cot(y) + xcsc^2(y)] if xy = ln(x cot y).
Top answer:
from xy = ln(x coty) x dy/dx + y = (x(-csc^y dy/dx) + coty)/(x coty) cross-multiply (x^2)(coty)dy/dx
Read more.
verify (csc^4-1)/cot^2x=2+cot^2x
So this is what I have so far on the left side (csc^2x+1)(cscx+1)(cscx-1)/cot^2x
Top answer:
recall that 1 + cot^2 x = csc^2 x as a variation of the Pythagorean identity so LS =
Read more.
use the quotient and reciprocal identities to simplify the given expression
cot t sin t csc t sin t tan t cot t cot t sec t
Top answer:
cot t sin t csc t sin t tan t cot t cot t sec t
Read more.
Use Newton's method to approximate a root of the equation (2 x^3 + 4 x + 4 =0) as follows.
Let (x_1 = -1\) be the initial
Top answer:
First of all, why not reduce it to x^3 + 2x + 2 = 0 Your iteration formula should be x<sub>new</b> =
Read more.
Use Newton's method to approximate a root of the equation 3sin(x)=x as follows.
Let x1=1 be the initial approximation. The second
Top answer:
You are on the right track! x1=1, x2=-1.455, x3=-3.787, x4=-2.140, ... eventually it will settle on
Read more.
Use Newton's method to approximate a root of the equation 3sin(x)=x as follows.
Let x1=1 be the initial approximation. The second
Top answer:
See: http://www.jiskha.com/display.cgi?id=1283924839
Read more.
Related Questions
Let f be a differentiable function such that f(3) = 2 and f'(3) = 5. If the tangent line to the graph of f at x = 3 is used to
If the local linear approximation of f(x) = 3sin x + e3x at x = 2 is used to find the approximation for f(1.9), then the % error
What is the first step. Explain please.
Which expression is equivalent to cos^2x + cot^2x + sin2^x? a) 2csc^2x b) tan^2x c)
Use Newton's method to approximate a root of the equation 3sin(x)=x as follows.
Let x1=1 be the initial approximation. The second
Use Newton's method to approximate a root of the equation 5sin(x)=x as follows.
Let x1=2 be the initial approximation. The second
If the local linear approximation of f(x) = 2cos x + e2x at x = 2 is used to find the approximation for f(2.1), then the % error
Simplify (cos x)/(sec(x) + 1)
a. cot^2 x - cot^2 x * cos x b. cot^2 x + cot^2 x * cos x c. cos^2 x + cos x d. cot^2 x - cot^2 x *
If the local linear approximation of f(x)=4x+e^2x at x=1 is used to find the approximation for f(1.1), then the % error of this
Verify the identity.
(csc(2x) - sin(2x))/cot(2x)=cos(2x) =csc(2x)/cot(2x) - sin(2x)/cot(2x) =csc(2x)/cot(2x) - cos(2x) Is this
Factorthen use fundamental identities to simplify the expression below and determine which of the following is not equivalent
