A 47.0 g golf ball is driven from the tee with an initial speed of 54.0 m/s and rises to a height of 23.8 m.
 👍
 👎
 👁
 ℹ️
 🚩

 👍
 👎
 ℹ️
 🚩

 👍
 👎
 ℹ️
 🚩
Answer this Question
Similar Questions

CHEM
The mass of a golf ball is 45.9g. If it leaves the tee with a speed of 72.0 m/s, what is its corresponding wavelength? Express your answer numerically in meters. Would the correct answer be: lambda=h/mv lambda=6.626*10^34/(45.9g)(72.0m/s)

physics
A golf club strikes a 0.040kg golf ball in order to launch it from the tee. For simplicity, assume that the average net force applied to the ball acts parallel to the ball’s motion, has a magnitude of 7950 N, and is in contact with the ball for a

physics  please help
A golf ball of mass 0.045 kg is hit off the tee at a speed of 48 m/s. The golf club was in contact with the ball for 5.4 103 s. (a) Find the magnitude of the impulse imparted to the golf ball. (b) Find the magnitude of the average force exerted on the

physics
On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a golf club improvised from a tool. The freefall acceleration on the moon is 1/6 of its value on earth. Suppose he hits the ball with a speed of 25 m/s at an angle of 28°

physics
A ball is thrown vertically upward with an initial speed of 20 m/s. Two seconds later, a stone is thrown vertically (from the same initial height as the ball) with an initial speed of 24 m/s. At what height above the release point will the ball and stone

Science
A golfer hits a golf ball with a club. The mass of the ball is 0.05 kg. The ball accelerates at 2,000 m/s2. What is the net force, to the nearest newton, that accelerates the ball? I know the answer is 50, but I don't know how to do it!

English/ Reading
Please check my answer thank you very much Read the paragraph to answer the question. Anyone can walk around a golf course. Anyone can hit a golf ball with a golf club. To do so, a person doesn't have to know the names or numbers of the different clubs. He

Physics
A golf ball is hit with an initial velocity of 15 meters per second at an angle of 35 degrees above the horizontal. What is the vertical component of the golf ball's initial velocity? a)8.6 m/s b)9.8 m/s c)12 m/s d)15 m/s I know you use 15cos 35 feta to

Science 10
A person hits a 45g golf ball. The ball comes down on a tree root and bounces straight up with an initial speed of 14.0 m/s. Determine the height the ball will rise after the bounce The equation is height= 1/2 velocity^2 / g where g is 9.8m/s^2

Algebra
A golf ball is struck by a 60degree golf club at an initial velocity of 84 feet per second. The height of the golf ball in feet is given by the quadratic function h(x)= 16 x^2/(42)^2+72.7/42x where x is the horizontal distance of the golf ball from the
Still need help?
You can ask a new question or browse existing questions.