mr. henderson has 2 bouncy ball vending machines. he buys one bag of the 27 millimeter balls and one bag of the 40 millimeter balls. he puts an equal number of each in the machine. how manu bouncy balls does he put in each machine?
I HAVE NO IDEA THATS WHY I ASKED FOR HELP BUT U DON'T EVEN EXPLAIN ANY THING SO HOW AM I SUPPOSED TO KNOW TBE STUPID ANSWER. DUUUUUUHHHHHHH😒😒
how big is the machine?
130
bouncy balls
130 bouncy balls in all
2340
WHAT IS THE TRUE ANSWER
115
To find out how many bouncy balls Mr. Henderson puts in each machine, we need to consider the ratio between the sizes of the two types of balls: 27 millimeter balls and 40 millimeter balls.
First, let's define the variables:
Let x be the number of 27 millimeter balls.
Let y be the number of 40 millimeter balls.
Since he puts an equal number of each type in the machine, the ratio of the number of 27 millimeter balls to the number of 40 millimeter balls is 1:1. This can be mathematically represented as:
x / y = 1 / 1
To solve for x and y, we can set up a system of equations using the given information.
We know that Mr. Henderson buys one bag of 27 millimeter balls and one bag of 40 millimeter balls. Let's assume each bag contains n number of balls. The total number of 27mm balls would be n * x, and the total number of 40mm balls would be n * y.
Since the total number of 27mm balls and 40mm balls must be equal, we can set up the equation:
n * x = n * y
Simplifying this equation, we get:
x = y
Now, we have two equations:
x / y = 1 / 1 (Equation 1)
x = y (Equation 2)
We can substitute Equation 2 into Equation 1:
y / y = 1 / 1
This simplifies to:
1 = 1
Since this equation is always true, it means that any value of x and y that satisfies Equation 2 will work.
Therefore, Mr. Henderson can put any number of bouncy balls in each machine as long as the number of 27 millimeter balls and 40 millimeter balls are equal.