Mary has two tanks of fish. If she transfers 15 fish from the larger tank to the smaller tank then the number of fish in the smaller tank
will be 5/7 of the number of fish in the large, tank. Given that there are 35 fish in the smaller tank originally, find the number of fish in the larger tank before the transfer of fish.
I did one, now you try.
Let's assume the number of fish in the larger tank before the transfer is "x".
According to the problem, if Mary transfers 15 fish from the larger tank to the smaller tank, the number of fish in the smaller tank will be 5/7 of the number of fish in the larger tank.
Therefore, the number of fish in the smaller tank after the transfer will be (5/7)x.
We know that there are 35 fish in the smaller tank originally, so we can set up an equation using this information:
(5/7)x = 35
To find the value of x, we can solve this equation for x.
Multiplying both sides of the equation by 7/5, we get:
x = 35 * (7/5)
Calculating this, we find:
x = 49
Therefore, the number of fish in the larger tank before the transfer is 49.