Points x and y are respectively 12m north and 5m east of point z.calculate xy

13m

13

How did you get 13 as your answer . please show workings

Use the Pythagorean Theorem.

a^2 + b^2 = c^2

12^2 + 5^2 = C^2

To calculate the distance between points x and y, which are respectively 12 meters north and 5 meters east of point z, we can use the Pythagorean theorem.

First, let's consider the vertical distance between points x and y, which is the same as the difference in their north-south coordinates. In this case, point x is 12 meters north of point z.

Next, let's consider the horizontal distance between points x and y, which is the same as the difference in their east-west coordinates. In this case, point y is 5 meters east of point z.

Now, we can construct a right triangle with one side representing the vertical distance (12 meters) and the other side representing the horizontal distance (5 meters). The hypotenuse of this right triangle will represent the distance between points x and y (xy).

Using the Pythagorean theorem, we can calculate the length of the hypotenuse:

xy² = (vertical distance)² + (horizontal distance)²
xy² = 12² + 5²
xy² = 144 + 25
xy² = 169

Taking the square root of both sides gives us:

xy = √169

Calculating the square root of 169, we find that:

xy = 13 meters

Therefore, the distance between points x and y, xy, is 13 meters.