CALCULATE THE DECREASE IN TEMPERATURE FOR 22.0 G SILVER THAT LOSES 625 J
Well, if silver loses 625 J of energy, it might go from being silver-hot to silver-lukewarm. But let's be scientific about it! To calculate the decrease in temperature, we need to know the specific heat capacity of silver. Without that information, I'm afraid I can't give you a precise answer. However, I can assure you that the temperature will definitely decrease. So, you won't have a silver lining when it comes to temperature!
To calculate the decrease in temperature for a given amount of silver that loses a certain amount of energy, we need to use the specific heat capacity formula:
q = mcΔT
where:
q is the heat energy lost (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)
In this case, we are given:
m = 22.0 g
q = -625 J (negative because energy is lost)
c = specific heat capacity of silver (we'll assume it is 0.24 J/g°C)
Rearranging the equation, we can solve for ΔT:
ΔT = q / (mc)
Substituting the given values:
ΔT = -625 J / (22.0 g * 0.24 J/g°C)
Calculating this, we get:
ΔT = -2.7°C
Note: The negative sign indicates that the temperature of the silver has decreased.
To calculate the decrease in temperature for a substance, you can use the formula:
ΔT = Q / (m * Cp)
Where:
ΔT is the change in temperature
Q is the amount of heat gained or lost by the substance
m is the mass of the substance
Cp is the specific heat capacity of the substance
In this case, you are given:
Q = -625 J (negative because the silver is losing heat)
m = 22.0 g
Cp = specific heat capacity of silver
Now, you need to find the specific heat capacity of silver. The specific heat capacity of a substance represents the amount of heat required to raise the temperature of one gram of that substance by one degree Celsius.
The specific heat capacity of silver is 0.235 J/g°C.
Now, plug in the given values into the formula:
ΔT = (-625 J) / (22.0 g * 0.235 J/g°C)
Simplifying the equation gives:
ΔT = -27.66 °C
Therefore, the decrease in temperature for the 22.0 g of silver is -27.66 °C. Note that the negative sign indicates a decrease in temperature.
Joules = mass Ag x specific heat Ag x delta T.
You know mass Ag, look up sp. h. Ag, you know J, solve for delta T.