a ball projected vertically upwards from the top of the tower 60 meters high with a velocity of 30 meters
per second. what is the maximum height above the ground? how long does it take to reach the ground?
V²=u²-2gh
At hmax v=0
0=30²-2x10xh
0=900-20h
20h=900
h= 900÷ 20
h=45
hmax = 45 + 60= 105 m
For time
V=u + gt
0=30-10t
10t=30
t=30÷10
Time taken to reach the ground
h=ut+½gt²
U=0 when body falls downward
105=0xt +½x10xt²
105=5t²
t²= 21
t=4.5
Total time taken to reach the ground=>3+4.5=7.5 seconds.
V²=u²-2gh
At hmax v=0
0=30²-2x10xh
0=900-20h
20h=900
h= 900÷ 20
h=45
hmax = 45 + 60= 105 m
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For time
V=u + gt
0=30-10t
10t=30
t=30÷10
Time taken to reach the ground
h=ut+½gt²
U=0 when body falls downward
105=0xt +½x10xt²
105=5t²
t²= 21
t=4.5
Total time taken to reach the ground=>3+4.5=7.5 seconds.