A tennis ball is projected
horizontally from the top of a cliff
50m high with a velocity of 10ms -1 ,
find
(a) the time taken to reach the ground
(b) the distance from the foot of the
cliff to where the ball hits the ground.
vertical:
h=1/2 g t^2 solve for t
horizontal: 10m/s*t
I need an answer
Please I need answers for that question
To find the time taken to reach the ground and the distance from the foot of the cliff to where the ball hits the ground, we can use the equations of motion for projectile motion.
In this case, the ball is projected horizontally, so there is no initial vertical velocity.
Let's break down the problem:
(a) Finding the time taken to reach the ground:
Using the equation for vertical displacement in projectile motion, we have:
H = (1/2) * g * t^2
Given that the height of the cliff is 50m, and the acceleration due to gravity is approximately 9.8m/s^2, we can rearrange the equation to solve for t:
t^2 = (2 * H) / g
t^2 = (2 * 50) / 9.8
t^2 = 10.2
t ≈ √10.2
t ≈ 3.19 seconds
Therefore, the time taken to reach the ground is approximately 3.19 seconds.
(b) Finding the distance from the foot of the cliff to where the ball hits the ground:
Since the ball is projected horizontally, its horizontal velocity remains constant throughout its trajectory.
Using the equation for horizontal displacement in projectile motion:
S = v * t
Given that the initial horizontal velocity (v) is 10m/s and the time taken to reach the ground (t) is 3.19 seconds, we can calculate the distance (S):
S = 10 * 3.19
S ≈ 31.9 meters
Therefore, the distance from the foot of the cliff to where the ball hits the ground is approximately 31.9 meters.