When you reverse the digits in a certain two digit number you increase its value by 27. Find the number if the sum of its digits is 7.

1 + 6

2 + 5
3 + 4

Which of those pairs meet the other criterion?

2+5?

52 - 27 = 25

Yep!

Pls i don't your solving

To solve this problem, let's represent the two-digit number as a 10s digit and a units digit. Let's say the 10s digit is x and the units digit is y.

The original number then can be represented as 10x + y.

Reversing the digits results in a new number represented as 10y + x.

According to the problem statement, when we reverse the digits, we increase the original number by 27. So, we can write the equation as:

10y + x = 10x + y + 27

Now, let's simplify the equation:

10y - y = 10x - x + 27

9y = 9x + 27

Dividing both sides by 9:

y = x + 3

The second given condition states that the sum of the digits is 7. So, we can write another equation:

x + y = 7

Now we have a system of two equations:

y = x + 3
x + y = 7

Substituting the first equation into the second equation:

x + (x + 3) = 7

Simplifying the equation:

2x + 3 = 7
2x = 7 - 3
2x = 4
x = 2

Now, substituting the value of x back into the first equation:

y = x + 3
y = 2 + 3
y = 5

Therefore, the number is 25.