A cars starts from rest and after 20 seconds its velocity becomes 108 km-1 find the acceleration of the car

Data

t =20 secs
vi=0
vf=108km/h------>m/s
= 108x1000/3600
= 30m/s
a=?
Solution
a= vf-vi/t
=(30) - (0)/(20)
= 30/20
Result
a=1.5 m/s²

Thank you For your help

I am amazed

To find the acceleration of the car, we can use the equation:

Acceleration = (Final Velocity - Initial Velocity) / Time

Here, the initial velocity is 0 km/h since the car starts from rest, the final velocity is 108 km/h, and the time is 20 seconds.

First, let's convert the velocities from kilometers per hour (km/h) to meters per second (m/s) since the units need to be consistent:

1 km/h = 1000 m/3600 s = 5/18 m/s

So, the initial velocity in m/s is 0 km/h * (5/18 m/s per km/h) = 0 m/s,
and the final velocity in m/s is 108 km/h * (5/18 m/s per km/h) = 30 m/s.

Now, we can substitute these values into the acceleration formula:

Acceleration = (30 m/s - 0 m/s) / 20 s = 30 m/s / 20 s = 1.5 m/s^2

Therefore, the acceleration of the car is 1.5 m/s^2.

a=changevelocity/time=108/20 km/sec^2=5.4km/sec which is a great acceleration.

Did you mean km/hr? Then divide 108 by 1000/3600 to get m/s

a then= Vin m/s/20

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