Kendra deposited a total of $9,000 between two saving accounts bearing simple interest. One of the accounts has an interest rate of 3% while the other rate is 4%. If the total interest earned after one year is $320, find the amount deposited into each of the accounts

just add up the interest in the parts. It must equal the whole amount specified.

If $x is at 3%, then the rest (9000-x) is at 4%. So,

.03x + .04(9000-x) = 320

i got 4000 is that right?

correct

Kendra deposited a total of $9,000 between two saving accounts bearing simple interest. One of the accounts has an interest rate of 3% while the other rate is 4%. If the total interest earned after one year is $320, find the amount deposited into each of the accounts.

I got 1333 for 3% and 7667 for 4% is this right

To find the amount deposited into each of the accounts, we can set up a system of equations based on the given information.

Let's assume the amount deposited into the account with a 3% interest rate is x dollars. Therefore, the amount deposited into the account with a 4% interest rate would be (9000 - x) dollars (since the total deposited amount is $9,000).

Now, we can calculate the interest earned on each account. The interest earned on the account with a 3% interest rate would be (0.03x), and the interest earned on the account with a 4% interest rate would be (0.04 * (9000 - x)).

According to the given information, the total interest earned after one year is $320. Thus, we can set up the following equation:

0.03x + 0.04(9000 - x) = 320

Now, let's solve this equation to find the value of x, which represents the amount deposited into the account with a 3% interest rate.

0.03x + 0.04(9000 - x) = 320
0.03x + 360 - 0.04x = 320
-0.01x = -40
x = (-40) / (-0.01)
x = 4000

Therefore, Kendra deposited $4,000 into the account with a 3% interest rate, and ($9,000 - $4,000) = $5,000 into the account with a 4% interest rate.