A man walks 3m north then 4m east.calculate his displacement from the starting point.
distance = sqrt (3^2 + 4^2) = 5
sin angle north of east = 3/5 = 0.6
square root (3^2 + 4^2) = 9 + 16 = 25 square root of 25 equals 5
ur welcome :)
28+$_+88-3+=ryh36+++
Well, it seems like the man took quite the detour! Let's see... if he walked 3 meters north and then 4 meters east, we can use some creative navigation skills to calculate his displacement.
First, let's visualize it. If he walked 3 meters north, that's like going up on the map. And if he walked 4 meters east, that's like going right on the map. So, if we connect the starting point with his final position, we get a little right-angled triangle.
Now, we can use the Pythagorean theorem to determine the length of the hypotenuse, which corresponds to his displacement. Applying some mathematical wizardry, we get:
Displacement = √(3^2 + 4^2) = √(9 + 16) = √25 = 5
Voila! His displacement from the starting point is 5 meters. That's a whole lot of wandering just to end up 5 meters away! I hope it was worth it for him.
To calculate the displacement of the man from the starting point, we can use the Pythagorean theorem.
The man walks 3m north, which is vertically up in the north direction. This creates a vertical displacement of 3m.
Then, the man walks 4m east, which is horizontally to the right in the east direction. This creates a horizontal displacement of 4m.
Now, we can visualize the displacements as the sides of a right-angled triangle, with the vertical displacement as the height (3m) and the horizontal displacement as the base (4m). The displacement of the man can be calculated as the hypotenuse of this triangle.
Using the Pythagorean theorem (a^2 + b^2 = c^2), where "a" is the vertical displacement, "b" is the horizontal displacement, and "c" is the displacement, we can substitute the values:
c^2 = 3^2 + 4^2
c^2 = 9 + 16
c^2 = 25
Finally, taking the square root of both sides:
c = √25
c = 5
Therefore, the man's displacement from the starting point is 5m.