an antelope moving with constant acceleration covers the distance between two points 70.0m apart in 7.00 s.Its speed as it passes the second points is 15.0m/s.
a.What is its speed at the fist poin?
b.What is ita acceleration?
the average speed is 10.0 m/s
... 70.0 m / 7.00 s
1st point speed is 5.00 m/s
... 10 = (15 + 5) / 2
acceleration is (10.0 m/s / 7.00 s)
To determine the answers to your questions, we can use the kinematic equations of motion. These equations relate the initial velocity (v0), final velocity (v), acceleration (a), displacement (s), and time (t). In this case, we have the distance between two points (displacement) and the time taken to cover this distance.
Let's divide the solution into two parts, starting with the first question:
a) What is its speed at the first point?
To find the speed at the first point, we need to calculate the initial velocity (v0). Given that the antelope covers a distance of 70.0 m in a time of 7.00 s and its speed at the second point (v) is 15.0 m/s, we can use the equation:
s = (v0 + v) * t / 2
Substituting the given values, we have:
70.0 m = (v0 + 15.0 m/s) * 7.00 s / 2
Rearranging the equation to solve for v0, we have:
v0 = (2 * s / t) - v
Plugging in the given values, we get:
v0 = (2 * 70.0 m / 7.00 s) - 15.0 m/s = 20.0 m/s
Therefore, the speed of the antelope at the first point is 20.0 m/s.
b) What is its acceleration?
To find the acceleration, we can use the following equation:
v = v0 + a * t
Given that the final velocity (v) is 15.0 m/s, the initial velocity (v0) is 20.0 m/s, and the time (t) is 7.00 s, we can rearrange the equation to solve for acceleration (a):
a = (v - v0) / t
Substituting the given values into the equation, we have:
a = (15.0 m/s - 20.0 m/s) / 7.00 s = -5.0 m/s^2
Therefore, the acceleration of the antelope is -5.0 m/s^2. The negative sign indicates that the antelope is decelerating or slowing down.
In summary:
a) The speed at the first point is 20.0 m/s.
b) The acceleration is -5.0 m/s^2.