A cash register contains only ten dollar and tenty dollar bills. It contains three times as many ten dollar bills as twenty dollar bills and the total amount of money in the cash register is $1,950. How many ten dollar bills are in the cash register?
incorrect
number of twenties --- x
number of tens ------- 3x
20x + 10(3x) = 1950
50x =1950
x = 39
so there are 39 twenties and 117 tens
check:
39(20) + 117(10) = 1950
3Ten=Twenty
20*twenty+10*ten=1950
20*2Ten+10Ten=1950
50 ten=1950
tens= 39
twentys=13
yes correct thank you so much!!!!
To find the solution, let's assign variables to represent the number of ten dollar bills and twenty dollar bills in the cash register.
Let's say the number of ten dollar bills is 'x'.
Since it's given that there are three times as many ten dollar bills as twenty dollar bills, we can say the number of twenty dollar bills is 'x/3'.
The value of each ten dollar bill is $10, so the total value of the ten dollar bills is 10x.
Similarly, the value of each twenty dollar bill is $20, so the total value of the twenty dollar bills is 20 * (x/3) = 20x/3.
We know that the total amount of money in the cash register is $1,950.
Considering the value of both the ten and twenty dollar bills, we can write the equation:
10x + (20x/3) = 1950
To solve this equation, we can multiply through by 3 to eliminate the fraction:
30x + 20x = 5850
50x = 5850
Now we can solve for 'x' by dividing both sides of the equation by 50:
x = 5850/50
x = 117
Therefore, there are 117 ten dollar bills in the cash register.